the final speed in m/s of the 10.0 kg is 2.53 m/s .
<u>Step-by-step explanation:</u>
Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:
We know that in an elastic collision :
⇒ Total kinetic energy before collision = Total kinetic energy after collision
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the final speed in m/s of the 10.0 kg is 2.53 m/s .
The equation of the height as a function of time for this case is given by:
h (t) = - 16t ^ 2 + 10t + 100
By the time the egg hits the ground we have:
-16t ^ 2 + 10t + 100 = 0
We look for the roots of the polynomial:
t1 = -2.2069555463432966
t2 = 2.8319555463432966
As it is about time, we use the positive root:
t = 2.83 s
Answer:
it hits the ground at:
t = 2.83 s
Isn't it (-3,3) that's what I think because it's 1 2 3 but I don't know