20 units im shure i took the test'
Answer:
(2, 13)
Step-by-step explanation:
Since they both equal y, you can equal them to each other.
8x - 3 = 2x + 9
Subtract 2x from both sides.
6x - 3 = 9
Add 3 to both sides.
6x = 12
Now divide 6 on both sides.
x = 2
Now that we have found x, we need to find y. Just plug in x to the equations.
y = 2(2) + 9
y = 4 + 9
y = 13
Now, if the next equal has the same y, then both are true.
8(2) -3 = y
16-3=y
13 = y
So therefor, both x and y are true.
The graph shows a
piecewise function, meaning that different functions are shows at different intervals (ranges of x-values).
1) One of the graphs is part of a parabola, meaning the equation is quadratic (has

). That equation must be

.
2) The other graph is a straight line, meaning it must be a linear equation. That equation must be x + 4.
Looking at the entire graph, you can see that the parabola starts from the left and ends with an open circle at x=2. An open circle means that the graph doesn't have a value at that point, x=2. The linear line starts with a filled point at x=2 and continues to the right. That means we're looking for the choice where:
1)

Since x=2 cannot be a point in the graph, and less than 2 means that the graph includes everything to the left of 2, but not including 2
2)

Since x=2 is a point in the graph, and greater than or equal to 2 means that the graph includes 2 and everything to the right of it
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Answer: C)
For this problem, you are to multiply the numbers and add the exponents for the variables
10*3= 30
x*x^4= x^5
y^5*y^6= y^11
z^3*z^3= z^6
the answer to the question is 30x^5y^11z^6