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mote1985 [20]
4 years ago
14

The Kwans are saving for their daughter’s college education. If they deposit $12,000 in an account bearing 6.4% interest compoun

ded continuously, how much will be in the account when Ann goes to college in 12 years?
Mathematics
2 answers:
Alla [95]4 years ago
5 0

Answer:

 

$25,865.41

Step-by-step explanation:

11111nata11111 [884]4 years ago
3 0
This is calculated using the formula of: A = Pe(rt), where A is the total amount, P is the principal amount, e is mathematical constant approximately equal to 2.71828, r is the rate of interest, then t is the time in years.

Given we have the P as $12,000, r is 0.064 and t is 12, we expressed these values to the formula as;

A = Pe(rt)
A = 12,000.e(0.064 x 12)
A = 12,000 x 2.71828e
A = 12,000 x 2.155
A = $25,860

Therefore the money that Ann will have in 12 years is $25,860.
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Question 5: 10 pts
victus00 [196]

Answer:

6.7i + 7.4j

Step-by-step explanation:

if the angle starts from the East (direction of positive x-axis)

then the y (j) component is 10*sin(42) = 6.7

and x (i) component is 10*cos(42) = 7.4

4 0
2 years ago
The area A of a triangle with base b and height h is given by A = = bh. Find the area when b = 18 m (meters) and h = 30 m.
Pie

Answer:

Area = 270m^2

Step-by-step explanation:

Given

A = \frac{1}{2}bh

b = 18m

h = 30m

Required

Solve for A

Simply substitute 18 for b and 30 for h

A = \frac{1}{2}bh

A = \frac{1}{2} * 18 * 30

A = 270

Hence:

The area is

Area = 270m^2

6 0
3 years ago
What is the value of x? Enter your answer in the box. x =
creativ13 [48]

x=5

a^+b^=c^

a^+12^=13^

a^+144=169

a^=25

a=square root of 25

a=5

4 0
4 years ago
if we have a geometric series with u1 = 2.1 and r= 1.06, what would the least value of n be such that Sn > 5543?
bulgar [2K]

Answer:

  88

Step-by-step explanation:

Write the expression for the sum in the relation you want.

  Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)

  Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)

The relation we want is ...

  Sn > 5543

  35(1.06^n -1) > 5543 . . . . substitute for Sn

  1.06^n -1 > 5543/35 . . . .  divide by 35

  1.06^n > 5578/35 . . . . . . add 1

  n·log(1.06) > log(5578/35) . . . take the log

  n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n

The least value of n such that Sn > 5543 is 88.

3 0
3 years ago
A dolphin swam 712 miles in 38 hour. What was its average speed in miles per hour (mph)?
Vilka [71]
To find miles per hour you divide the number of miles by the number of hours

(7 1/2)/(3/8) = (15/2)(8/3) = 20 mph
4 0
3 years ago
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