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3 years ago

How to solve y-5=3-9 (y+2)

Mathematics

2 answers:

solniwko [45]3 years ago

4 0

Y-5=3-9y-18 expand it
Y-5=-9y-15 simplify
Y-5+9y=-15
10y=-10
Y=-1

Goshia [24]3 years ago

3 0

Y - 5 = 3 - 9(y + 2)

Expand the brackets

y - 5 = 3 - 9y + 18

Move y to one side, and constants to the other

10y = 26

Solve for y

y = (26 / 10) = 2.6

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What is the decay factor of the exponential function represented by the table?

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Option 2 is correct.

Step-by-step explanation:

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Upon looking at our table we can see that every time x increases by one our y value remains one-third of the previous value.

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4 years ago

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3 years ago

12a^3b^2 +18a²b^2 – 12ab^2<br> Factor completely

AleksAgata [21]

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<u>Solution:</u>

Given, expression is $12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

We have to factorize the given expression completely.

Now, take the expression

$12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

Taking $b^2$ as common term,

$b^{2}\left(12 a^{3}+18 a^{2}-12 a\right)$

Taking "a" as common term,

$b^{2}\left(a\left(12 a^{2}+18 a-12\right)\right)$

Taking "6" as common term,

$b^{2}\left(a\left(6\left(2 a^{2}+3 a-2\right)\right)\right)$

Splitting "3a" as "4a - a" we get,

$b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)$

$\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}$

Hence, the factored form of given expression is $6 a b^{2}(a+2)(2 a-1)$

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3 years ago

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