Question

A right triangle has side lengths 5 , 12 , and 13 as shown below. Use these lengths to find tanX , cosX , and sinX

Answer 1

Answer:

$\text{sin}(x)=\frac{12}{13}$

$\text{cos}(x)=\frac{5}{13}$

$\text{tan}(x)=\frac{12}{5}$

Step-by-step explanation:

Consider:

$\text{sin}(x)=\frac{\text{Opposite}}{\text{Hypotenuse}}$

$\text{cos}(x)=\frac{\text{Adjacent}}{\text{Hypotenuse}}$

$\text{tan}(x)=\frac{\text{Opposite}}{\text{Adjacent}}$

I will apply adjacent side to angle $x$ as 5. and opposite side to angle $x$ as 12.

So,

$\text{sin}(x)=\frac{12}{13}$

$\text{cos}(x)=\frac{5}{13}$

$\text{tan}(x)=\frac{12}{5}$