Answer:
30
Step-by-step explanation:
Since the question says that it took her 45 minutes per hour, you can use that to find the distance of the route she took.
45 miles: 60 minutes
15 miles: 20 minutes ----------------cross multiply (20x45 and then divide by 60)
Therefore, if she is going to use the same route in reverse, the distance would be 15 miles.
Use the formula for speed:
speed= distance/time
= 15/0.5 ---------- 0.5 hours is the same as 30 minutes
= 30
Answer:
can youpost a pic of the number line? its be helpful in solving your question.
Step-by-step explanation:
Answer:
15) 3.2
17) 13.4
Step-by-step explanation:
To find the missing lengths, you need to use the Pythagorean theorem:
a² + b² = c²
In this form, "c" represents the length of the hypotenuse and "a" and "b" represent the lengths of the other two sides.
You are trying to find one of the side lengths (not the hypotenuse) in 15). To find the other length, you can plug the other values into the equation and simplify to find "b".
15) a = 4.1 c = 5.2
a² + b² = c² <----- Pythagreom Theorem
(4.1)² + b² = (5.2)² <----- Plug values in for "a" and "c"
16.81 + b² = 27.04 <----- Raise numbers to the power of 2
b² = 10.23 <----- Subtract 16.81 from both sides
b = 3.2 <----- Take the square root of both sides
You are trying to find the hypotenuse in 17). Since you have been given the lengths of the other sides, you can plug them into the equations and simplify to find "c".
17) a = 4.4 b = 12.7
a² + b² = c² <----- Pythagreom Theorem
(4.4)² + (12.7)² = c² <----- Plug values in for "a" and "b"
19.36 + 161.29 = c² <----- Raise numbers to the power of 2
180.65 = c² <----- Add
13.4 = c <----- Take the square root of both sides
Answer:
B. The relation is a function because each x-value corresponds to only one y-value.
Step-by-step explanation:
In order for a relation to be a function, each x-value must have only one y-value. Decimals and negative numbers are negligible.
<span>\int_c\vec f\cdot d\vec r, in two ways, directly and using stokes' theorem. the vector field \vec f = 5 y\vec i - 5 x\vec j and c is the boundary of s, the part of the surface z = 16 -x^2-y^2 above the xy-plane, oriented upward.</span>
