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nikitadnepr [17]
3 years ago
6

Mrs. Jackson made a line plot of the times it took students to complete a project.

Mathematics
1 answer:
Komok [63]3 years ago
8 0
This value is very different from the other values
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I need help....Help me please .
maks197457 [2]

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i cant see the picture

Step-by-step explanation:

5 0
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Will an object with a density of. 97 g/ml float or sink in water explain
Ainat [17]
I would say the object will float because the density of water is 999.99kg/m which is slightly less than 1g but still more than the object.
3 0
3 years ago
Solve the following ODE's: c) y* - 9y' + 18y = t^2
Nastasia [14]

Answer:

y = C_1e^{3t}+C_2e^{6t} + \dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

Step-by-step explanation:

y''- 9 y' + 18 y = t²

solution of ordinary differential equation

using characteristics equation

m² - 9 m + 18 = 0

m² - 3 m - 6 m+ 18 = 0

(m-3)(m-6) = 0

m = 3,6

C.F. = C_1e^{3t}+C_2e^{6t}

now calculating P.I.

P.I. = \frac{t^2}{D^2 - 9D +18}

P.I. = \dfrac{t^2}{(D-3)(D-6)}\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1-\frac{D}{6})^{-1}(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1+\frac{D}{6}+\frac{D^2}{36}+....)(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(1+\frac{D}{3}+\frac{D^2}{9}+....)(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

hence the complete solution

y = C.F. + P.I.

y = C_1e^{3t}+C_2e^{6t} + \dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})

7 0
3 years ago
What is 7x + 6x = ?<br>​
viva [34]

Answer:

  • 13x

Step-by-step explanation:

<u>Two ways to solve</u>

1.) Expand each term in the equation

  • 7x = x · x · x · x · x · x · x
  • 6x = x · x · x · x · x · x
  • Count all the x’s ⇒ There are 13 x’s ⇒ 13x

2.) Add the coefficients

  • 7 + 6 = 13
  • 7x + 6x = 13x

Hence,

Answer = 13x

8 0
3 years ago
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