1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
algol13
2 years ago
15

There are 12 boys and 16 girls in Marco's class (including Marco).What is the probability that a student chosen at random from M

arco's class will be a boy?
Mathematics
1 answer:
Len [333]2 years ago
5 0

Answer: 3:4 ratio or 3/4

Step-by-step explanation:

You might be interested in
What is the volume of 22.5 g of metal with a density of 2.81 g/cm
xz_007 [3.2K]

Answer:V = 72.1 cm³ - 50.0 cm³ = 22.1 cm³

D = mV=99.7g22.1cm³ = 4.51 g/cm³

Step-by-step explanation:

d = mV

m = d×V

V = md

DENSITY

Density is defined as mass per unit volume.

d = mV

Example:

A brick of salt measuring 10.0 cm x 10.0 cm x 2.00 cm has a mass of 433 g. What is its density?

Step 1: Calculate the volume

V = lwh = 10.0 cm × 10.0 cm × 2.00 cm = 200 cm³

Step 2: Calculate the density

d = mV = 433g200cm³ = 2.16 g/cm³

MASS

d = mV

We can rearrange this to get the expression for the mass.

m = d×V

Example:

If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass?

m = d×V = 500 mL × 1.11g1mL = 555 g

VOLUME

d = mV

We can rearrange this to get the expression for the volume.

V = md

Example:

What is the volume of a bar of gold that has a mass of 14.83 kg. The density of gold is 19.32 g/cm³.

Step 1: Convert kilograms to grams.

14.83 kg × 1000g1kg = 14 830 g

Step 2: Calculate the volume.

V = md = 14 830 g × 1cm³19.32g = 767.6 cm³

7 0
3 years ago
Helppppppp Asappppppp
MArishka [77]

Answer:

All of them

Step-by-step explanation:

2/2 is 1, and if the shaded part is 2/2, everything would be shaded.

3 0
3 years ago
Read 2 more answers
Plz help asap!!! Will give brainlest!!!
8090 [49]

Answer:

$4

Step-by-step explanation:

Total expenditure is $55

Breakdown

2 books cost $10

4 books cost $25

Subtotal for 6 books is 10+25=$35

Remaining amount from total is 55-35=$20

If each book costs approximately $5 then for $20, each book is 20/5=$4

5 0
3 years ago
What expression is equivalent to -0.2 - 4.9?
nasty-shy [4]

Answer:

A

Step-by-step explanation:

Adding a negative is the same as subtracting a positive

Keep Change Change

ex. -9.2 - 6.7 = -9.2 + -6.7

    Keep    Change     Change

   -9.2           +              -6.7

6 0
3 years ago
The spinner for a board game has eight colors the arrow can land on. What are the degrees of freedom for a goodness-of-fit test
Juliette [100K]

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

Number of colors that the arrow can land on = 8

We need to find the degrees of freedom for a goodness of fit test of the fairness of this spinner.

As we know that degree of freedom is 1 less than the size of sample.

So, Mathematically, it is expressed as below:

So, Degree of freedom would be

v=n-1\\\\v=8-1\\\\v=7

Hence, Option 'c' is correct.

7 0
3 years ago
Other questions:
  • In a randomly selected sample of 400 registered voters in a community, 160 individuals say that they plan to vote for Candidate
    11·1 answer
  • What is 4(2x-9) + 2 simplified
    14·2 answers
  • Thomas earned $17,000 last year for his part time job. He expects to earn 4% more each year. How much money will Thomas have ear
    15·1 answer
  • Can somebody please help with this ?? :)
    5·1 answer
  • What is the product?<br> (4x)(-3x^8) (-7x^3)<br> -84x1 12<br> -84x24<br> O 84x12<br> 84724
    15·1 answer
  • ___% of 300g =60g<br>what is in *____*​
    9·1 answer
  • What is the median?<br> 122235
    7·1 answer
  • 10 POINTS!! PPLZZZZZZ (MATH) :(stay safe):
    11·1 answer
  • There are 366 days in a leap year and 24 hours in a day. How many hours are in a leap year?
    5·1 answer
  • Help me please, I want the answer only.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!