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sergij07 [2.7K]
2 years ago
15

26 is what percent of 130? Please answer quickly no jokes.

Mathematics
1 answer:
Ostrovityanka [42]2 years ago
3 0

First, divide.

26 / 130 = 0.2

Second, multiply.

0.2 * 100% = 20%

Therefore, 26 is 20% of 130

Best of Luck!

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A. 1/5k - 2/3j and -2/3j + 1/5k

Step-by-step explanation:

Equivalent expressions are expressions that are the same even though they may appear different.When you plug in a value to represent a variable in these expression, they will give same answer when simplified.

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Step-by-step explanation:

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I need some help on this math problem, thanks so much
bekas [8.4K]

Answer:

The answer is C.

Step-by-step explanation:

Hit 'em with the Law of Sines.

sin(A)/a = sin(B)/b.

Let's say x is equal to "A", thus 5 is "a".

sin(x)/5 = sin(B)/b.

We could go for the obvious choice for "B", which would be the 90 degrees shown. To solve for the hypotenuse which will be "b", let's use the Pythagorean Theorem:

a^2 + b^2 = c^2

5^2 + 20^2 = c^2

25 + 400 = 425

sqrt(425) = about 20.6, which we can now substitute "b" with.

sin(x)/5 = sin(90)/20.6

sin(x)/5 = 1/20.6

sin(x)/5 = 0.04854...

sin(x) = 0.2427...

You can plug in sin^-1(0.2427) into your calculator, and you should end up with something like 14.047... which equates to answer choice C.

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2 years ago
A rose garden Is formed by jolning a rectangle and a semicircle, as shown below. The rectangle Is 23 ft long and 14 ft wide.Find
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Answer:

Area of the garden:

\begin{equation*} 398.93\text{ ft}^2 \end{equation*}

Explanation:

Given the below parameters;

Length of the rectangle(l) = 23 ft

Width of the rectangle(w) = 14 ft

Value of pi = 3.14

Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.

The radius(r) of the semicircle will now be;

r=\frac{d}{2}=\frac{14}{2}=7\text{ ft}

Let's now go ahead and determine the area of the semicircle using the below formula;

A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2

Let's also determine the area of the rectangle;

A_r=l*w=23*14=322\text{ ft}^2

We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}

Therefore, the area of the garden is 398.93 ft^2

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