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Lady bird [3.3K]
2 years ago
6

Suppose that the probabilities of a customer purchasing​ 0, 1, or 2 books at a book store are 0.2​, 0.3​, and 0.5​, respectively

. What is the expected number of books a customer will​ purchase?
Mathematics
1 answer:
svetlana [45]2 years ago
3 0

Answer:

Expectation number of books a customer will​ purchase  =  1.3

Step-by-step explanation:

x     :​ 0      1              2

p(x) :0.2​,  0.3​, and 0.5​

Expectation

E(X) = ∑x P(x)

      = 0 X 0.2 +1 X 0.3+ 2 X 0.5

     = 1.3

Expectation  E(X) =  1.3

Expectation number of books a customer will​ purchase  =  1.3

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Answer:

Step-by-step explanation:

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The formula for "average rate of change" is a.r.c. = --------------

                                                                                           b - a

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This is equivalent to  ---------------------------------------

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For Section A:  x changes from 1 to 2 and the function changes from 4(2)^1 to  4(2)^2:  8 to 16.  Thus, "change in function value" is 8 for a 1-unit change in x from 1 to 2.  Thus, in this Section, the a.r.c. is:

                 8

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Section B:  x changes from 3 to 4, a net change of 1 unit:  f(x) changes from

4(2)^3 to 4(2)^4, or 32 to 256, a net change of 224 units.  Thus, the a.r.c. is

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The a.r.c for Section B is 28 times greater than the a.r.c. for Section A.

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vovikov84 [41]

Answer:

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u know how u can sometimes cancel something out by doing the opposite.

This is one of those times as well. the opposite of ^2 = square root.

so if we take the square root of both sides, this will cancel out the^2 on the left side.

sqrt (x^2) = sqrt(81)

x = (+-) 9.....thats a positive and a negative sign...because the sqrt of 81 is both 9 and -9.

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