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vodka [1.7K]
2 years ago
11

in . 3.5 in 4 9 in 4 in . The triangular prism above has been created with two equilateral triangles and three congruent rectang

les . The height of the triangles is 3.5 inches . Find the surface area of the triangular prism . square inches

Mathematics
1 answer:
Viefleur [7K]2 years ago
7 0

Answer:

122 in²

Step-by-step explanation:

Applying,

S.A =  bh+ bl+bl+bl............. Equation 1

Where S.A = Surface area of the prism, b = base of the triangle, h = height of the triangle, l = lenghth of the prism

From the question,

Given: b = 4 in, h = 3.5 in, l = 9 in

Substitute these values into equation 1

S.A = 4×3.5+9×4+9×4+9×4

S.A = 14+108

S.A = 122 in²

Hence the surface area of the prism is 122 in²

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the shorter piece is 11 inches long

Step-by-step explanation:

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Given :

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2 years ago
Suppose that each time Giannis Antetokounmpo shoots a free throw, he has a 3/4 probability of success. If Giannis shoots three f
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Answer:

84.38% probability that he succeeds on at least two of them

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either Giannis makes it, or he does not. The free throws are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

He has a 3/4 probability of success.

This means that p = \frac{3}{4} = 0.75

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This means that n = 3

What is the probability that he succeeds on at least two of them

P(X \geq 2) = P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.75)^{2}.(0.25)^{1} = 0.4219

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P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4219 + 0.4219 = 0.8438

84.38% probability that he succeeds on at least two of them

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