Your answer is D. 16x² - 56xy + 49y².
A perfect square trinomial is the result of a squared binomial, like (a + b)². Using this example, the perfect square trinomial would be a² + 2ab + b², as that is what you get when you expand the brackets.
Therefore, to determine which of these is a perfect square trinomial, we have to see if it can be factorised into the form (a + b)².
I did this by first square rooting the 16x² and 49y² to get 4x and 7y as our two terms in the brackets. We automatically know the answer isn't A or B as you cannot have a negative square number.
Now that we know the brackets are (4x + 7y)², we can expand to find out what the middle term is, so:
(4x + 7y)(4x + 7y)
= 16x² + (7y × 4x) + (7y × 4x) + 49y²
= 16x² + 28xy + 28xy + 49y²
= 16x² + 56xy + 49y².
So we know that the middle number is 56xy. Now we assumed that it was (4x + 7y)², but the same 16x² and 49y² can also be formed by (4x - 7y)², and expanding this bracket turns the +56xy into -56xy, forming option D, 16x² - 56xy + 49y².
I hope this helps!
Answer:
35%
Step-by-step explanation:
% of guests who attended the wedding is number of guests who attended the wedding divided by the number of invited guests and the result multiplied by 100%
Therefore
28/80 x 100%
0.35 x 100%
35%
35% of the invited guests attended the wedding
Answer:
40 centimeters square.
Step-by-step explanation:
Area= length × width
8×5=40
Have a nice day
Given the following functions below,
Factorising the denominators of both functions,
Factorising the denominator of f(x),
Factorising the denominator of g(x),
Multiplying both functions,
The point of intersection is the point where lines intersect.
<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>
<em />
Given
<em />
<em> --- the number of lines</em>
<em />
<em> --- no three lines are concurrent</em>
<em />
When no three line are concurrent, it means that no three lines meet at the same point.
<u>So, the sequence of intersection is:</u>
- <em>0 intersection for 1 line</em>
- <em>1 intersection for 2 lines</em>
- <em>3 intersections for 3 lines</em>
- <em>6 intersections for 4 lines</em>
<em />
Following the above sequence, the number of intersections for n lines is:
In this case, 
So, we have:
<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>
<em />
Read more about lines of intersections at:
brainly.com/question/22368617
