The value of d in equation Q/R=8/d is 8R/Q.
Given an equation Q/R=8/d.
We are required to find the value of d in the given equation.
Equation is basically the relationship between two or more variables that are expressed in equal to form. The values that we enter is known as domain and the values that we get is known as range. It can be linear equation, quadratic equation, cubic equation.
The equation is :Q/R=8/d
We have to take d in right side of equal to sign and Q,R to the left side of right side of equal to sign.
d=8R/Q
Hence the value of d in equation Q/R=8/d is 8R/Q.
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Answer:
(p^2−6) (1-q(p^2-6))
Step-by-step explanation:
p^2−6−q·(p^2−6)^2
Put parentheses around the P^2-6 at the beginning of the expression
(p^2-6) -q (p^2−6)^2
Factor out (p^2−6)
(p^2−6) (1-q(p^2-6))
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⭐Here is Your Answer..!!!
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↪Cartesian Coordinates of the system....!!
↪X = rcos⊙ and Y = rsin⊙
↪since here Radius (r) = 10 units and Theta (⊙) = 225°
↪there fore substituting we get as ..
↪X = 10 ( cos 225° ) = 10 * -1/ root 2 = -7.071
↪Y = 10 ( sin 225° ) = 10 * -1/root2 = = -7.071
↪the cordinates are as follows
↪(x,y) = (-7.071, -7.071 )
