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Ne4ueva [31]
3 years ago
11

Can I get some help :/ ?

Mathematics
1 answer:
serious [3.7K]3 years ago
4 0
1.750
3.516540
4.354.2
5.3560
6.4.73
7.1277.2
8.4544
9.813000
10.0.02532
11.3160000
12.0.00335
13.26310
14. 918.7
15. 9320
16.8.42
17.45160000
18.0.005435
19.2450
20.656.9

Hope this helps!
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Please help help help!!!!!!​
kvasek [131]
<h2>Answer:</h2>

  • option (c) 2

<h2>Step-by-step explanation:</h2>

<u>First step</u> : Multiply

<u>Second step</u> : Add

9 × 2 + 3 + 6 + 9 = 36

\thereforeThe correct answer is 2.

3 0
1 year ago
PLEASEEE HELP MEE THIS IS DUE IN LESS THAN AN HOUR !!!!!
hjlf

Answer:

D.

Step-by-step explanation:

If you look at the graph, it says (1, 19.3) for one cubic centimeter.

Hope this helped :)

(Sorry if it is wrong)

8 0
3 years ago
Which of the following expressions is evuivalent to 5x-(4+2(x-1)
svetlana [45]

Answer:

3x-2

Step-by-step explanation:

7 0
2 years ago
Which of the following points lie in the solution set to the following system of inequalities? (1 point)
swat32

Answer:

the answer is

The point (1, −5) lie in the solution set

5 0
3 years ago
A human gene carries a certain disease from the mother to the child with a probability rate of 34%. That is, there is a 34% chan
eimsori [14]

Answer:

The probability that at least one of the children get the disease from their mother is P=0.7125.

Step-by-step explanation:

This can be modeled as a binomial random variable.

The parameter p=0.34 is the probability of a child being infected, and is constant and independent of the other events.

The parameter n=3 is the number of children  (sample size).

Then, we have to calculate the probabilty that at least one of the children get the disease from their mother. That is:

P(x\geq1)

The probability of exactly k children being infected can be calculated as:

P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}

Then, the easiest way to calculate this probability is using the complement: the value of the probability is 1 (or 100%) less the probability that no children gets infected.

P(x\geq1)=1-P(x=0)\\\\\\P(x=0) = \dbinom{3}{0} p^{0}(1-p)^{3}=1*1*0.2875=0.2875\\\\\\P(x\geq1)=1-0.2875=0.7125

3 0
3 years ago
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