Let width and length be x and y respectively.
Perimeter (32in) =2x+2y=> 16=x+y => y=16-x
Area, A = xy = x(16-x) = 16x-x^2
The function to maximize is area: A=16 x-x^2
For maximum area, the first derivative of A =0 => A'=16-2x =0
Solving for x: 16-2x=0 =>2x=16 => x=8 in
And therefore, y=16-8 = 8 in
Answer:
Step-by-step explanation:
A' (2,-3)
B' (5,-5)
C' (7,-3)
D' (5,-2)
Solution

For this case we can take square root in both sides and we have:
![3x-5=\pm\sqrt[]{19}](https://tex.z-dn.net/?f=3x-5%3D%5Cpm%5Csqrt%5B%5D%7B19%7D)
And solving for x we got:
![x=\frac{5\pm\sqrt[]{19}}{3}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B5%5Cpm%5Csqrt%5B%5D%7B19%7D%7D%7B3%7D)
then the solutions for this case are:
B and E
3^6 power. it would be 3 to the 6th power
2-3=1
4-5=20
1-2=1
i think this is it i have never really been good at this but i think it could be those one