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eimsori [14]
3 years ago
8

I need this question in order to finish! Please help

Mathematics
1 answer:
zavuch27 [327]3 years ago
3 0

Answer:

22

Step-by-step explanation:

Reminder: 3 sides can form a triangle if the sum of any two sides exceeds the third and the difference of any two sides is smaller than the third.

Therefore, the possible values of x are 22

:)

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In PQR, point S lies on QR. If PS is perpendicular to QR, which term describes PS?A. Perpendicular bisector
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It can't be for sure a perpendicular bisector cuz you don't know what kind of triangle you are dealing with so that one's out.  It's not necessarily an angle bisector either for the same reason. A median means that PS will go through the opposite side right in the center, and again, depending upon what type of triangle you have, this could be true...So it is an altitude, which is like a height of a triangle. It drops down from a vertex and forms a right angle with wherever it goes through. So D.
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How many solutions to y=2x-3 y=-x+3
Ivan

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y = 1

Step-by-step explanation:

I dunno what you need but that's the answer to y...

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If 3 × 8 = 24, which expression must equal 3?<br><br> 8 ÷ 24<br> 8 ÷ 3<br> 24 ÷ 8<br> 24 ÷ 3
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What is an equation of the line that passes through the point (-6,-8) and is parallel to the line x-2y=6?
vfiekz [6]

Answer:

y=\frac{1}{2}x-5

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)
  • Parallel lines always have the same slope and different y-intercepts

<u>1) Determine the slope (m)</u>

x-2y=6

Rearrange this equation into slope-intercept form (this will help us find the slope)

Subtract x from both sides

x-2y-x=6-x\\-2y=-x+6

Divide both sides by -2

y=\frac{1}{2} x-3

Now, we can identify clearly that the slope of the given line is \frac{1}{2} since it's in the place of m. Because parallel lines always have the same slopes, the line we're currently solving for would therefore have a slope of \frac{1}{2} as well. Plug this into y=mx+b:

y=\frac{1}{2}x+b

<u>2) Determine the y-intercept (b)</u>

y=\frac{1}{2}x+b

Plug in the given point (-6,-8)

-8=\frac{1}{2}(-6)+b\\-8=-3+b

Add 3 to both sides to isolate b

-8+3=-3+b+3\\-5=b

Therefore, the y-intercept is -5. Plug this back into y=\frac{1}{2}x+b:

y=\frac{1}{2}x-5

I hope this helps!

7 0
3 years ago
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