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blondinia [14]
2 years ago
13

One supplementary angle is 15 degrees less than twice the other. Find the measure of the two supplementary angles.

Mathematics
1 answer:
o-na [289]2 years ago
5 0

Hey there!

To find our answer, we need to set up a <u><em>system of equations. </em></u>Remember, <u><em>supplementary angles</em></u> equal 180 degrees when combined. We will call one of our angles A and the other one B. Let's set it up below! :)

A=2B-15 (one angle is 15 degrees less than twice the other)

A+B=180

We need to find one of our variables. To do this, we only put one variable in the equation. But how, there are two variables in both equations! Well, as you can see, we see the A is equal to 2B-15, so we can take 2B-15 and put it into the second equation in place of A because it is equal to A, and then we will only have Bs and we can solve for it. This method is known as solving systems of equations with <u><em>substitution.</em></u>

Let's solve with substitution!

2B-15+B=180

3B-15=180              We combine our Bs.

3B=195              We add 15 to both sides.

B= 65                We divide both sides by three.

Now, we need to find what A is, but this will be really easy to do! If you remember, our angles are supplementary, so when you combine them, we will get 180, as you can see in our second equation in our first system of equations. So, we simply subtract 65 from 180.

180-65=115

Our two angles are 65° and 115°.

We can also check this with the original problem.

If you double 65, we have 130. Then, if we subtract 15, we have 115. Systems of equations are a pretty awesome way to figure this out!

I hope this helps! Have a great day!

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A rectangle is twice as long as it is wide. If its length and width are both
puteri [66]

Answer:

a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle

Step-by-step explanation:

Let l = the original length of the original rectangle

Let w = the original width of the original rectangle

From the description of the problem, we can construct the following two equations

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Substitute equation #1 into equation #2

(2w+4)*(w+4)=(2w*w)+88

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collect like terms on the same side of the equation

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Since 4 is afactor of each term, divide both sides of the equation by 4

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The quadratic equation can be factored into (w+6)*(w-3)=0

Therefore w=-6 or w=3

w=-6 can be rejected because the length of a rectangle can't be negative so

w=3 and from equation #1 l=2*w=2*3=6

I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.

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