Since we have to solve this system graphically, we'll have to draw both lines.
To draw a line, simply build a little tables with two x,y values: for the first line we have

So, you can draw the points (0,3) and (1,2), connect them, and you'll have the graph of the line 
For the second line we have

So, you can draw the points (0,5) and (1,6), connect them, and you'll have the graph of the line 
Finally, we have to check where the two lines cross. If your drawing is accurate enough, you'll see that the point you're looking for is (-1, 4)
Answer:
Vertical angle=9.5°
Time to reach maximum height = 1.24seconds
Step-by-step explanation:
The maximum distance x is reached when rope swings to a maximum height, maximum height is gotten from the equation KE= 1/2MU^2 = MgH = MgL= Mgl(1- cos theta.
Where theta is the vertical angle, U=2m/s and L= 15m
2gl -2glcostheta=U^2
2gl U^2=2gl cos theta
But theta= Acos(1- U^2)/2gl
Acos(1-/(2×9.8×15)
Theta =9.5°
Maximum height li given by
Lsintheta
But X= UxT
T=X/UX= Lsintheta/U = 15sin9.5 /2 =1.24seconds
question no 39 isnot correct. they should be in i j k form