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damaskus [11]
3 years ago
7

The minimum of a parabola is located at (-1,-3).the point (9,1) Is also on the graph which equation can be solved to determine t

he value in the function representing the parabola?
Mathematics
1 answer:
Tju [1.3M]3 years ago
8 0

Answer:

(8,-2)

Step-by-step explanation:

9-1 and 1-3

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den301095 [7]

Hi there! In this problem, you should have the knowledge of three basic Trigonometric Ratio.

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Now that we know three basic ratio. Let's check each choices!

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This choice is wrong because we focus on the 50° angle. When we focus on 50°, sin50° should be d/x and not d/c.

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This choice is also wrong because in ratio, it's cos50° that adjacent/hypotenuse.

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This choice is correct! As ratio states, tanA = opposite/adjacent.

  • tan50° = x/c

This choice is wrong. x/c is a reciprocal of cosine which is 1/cos. We call the reciprocal of cosine as secant or sec in short.

  • cos50° = x/d

This choice is wrong as x/d is a reciprocal of sine which is 1/sin. We call the reciprocal of sine as cosecant or cosec/csc in short.

  • cos50° = c/x

This choice is right by the ratio. Nothing really much to explain since we follow by ratio that is defined.

Answer

  • tan50° = d/c
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Questions can be asked through comment.

Furthermore, tan also has its reciprocal form itself which is called cotangent also known as cot in short.

Hope this helps, and Happy Learning! :)

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Check the picture below.

to get the equation of any straight line, we simply need two points off of it, so let's use those in the picture

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\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{5}{6}}(x-\stackrel{x_1}{(-2)})\implies y-1=\cfrac{5}{6}(x+2) \\\\\\ y-1=\cfrac{5}{6}x+\cfrac{5}{3}\implies y=\cfrac{5}{6}x+\cfrac{5}{3}+1\implies y=\cfrac{5}{6}x+\cfrac{8}{3}

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