Answer:
- Area of the circle is 113.04 ft²
Step-by-step explanation:
Given:
- Diameter of circle = 12 feet
To Find:
Using formula:
![\\ \: \: \dashrightarrow \: \: \:{\underline{\boxed{ \bf{Area_{( circle)} = \pi r^2}}}} \\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%5C%3A%20%20%5C%3A%20%5Cdashrightarrow%20%5C%3A%20%20%5C%3A%20%20%5C%3A%7B%5Cunderline%7B%5Cboxed%7B%20%20%5Cbf%7BArea_%7B%28%20circle%29%7D%20%3D%20%5Cpi%20r%5E2%7D%7D%7D%7D%20%5C%5C%20%5C%5C)
<em>Where,</em>
- π = 3.14
- Diameter = 12 feet
- Radius = 12/2 = 6 feet
On substituting the required values, we get:
![\\ \: \: \dashrightarrow \: \: \: \sf Area_{(Circle)} = 3.14 \times {(6)}^{2} \\ \\ \\ \: \: \dashrightarrow \: \: \: \sf Area_{(Circle)} = 3.14 \times 36 \\ \\ \\ \: \: \dashrightarrow \: \: \: \sf Area_{(Circle)} = 113.04 \: {ft}^{2} \\ \\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%20%20%5C%3A%20%20%5C%3A%20%5Cdashrightarrow%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Csf%20Area_%7B%28Circle%29%7D%20%3D%20%20%20%203.14%20%5Ctimes%20%20%7B%286%29%7D%5E%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%5C%3A%20%20%5C%3A%20%5Cdashrightarrow%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Csf%20Area_%7B%28Circle%29%7D%20%3D%20%20%203.14%20%5Ctimes%2036%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%5C%3A%20%20%5C%3A%20%5Cdashrightarrow%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Csf%20Area_%7B%28Circle%29%7D%20%3D%20%20113.04%20%5C%3A%20%20%7Bft%7D%5E%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20)
Hence,
- Area of the circle is<u> </u>113.04 ft²
2.74 - (-19.4) = 22.14, so the freezer is 22.14°c colder. I hope that helps!
The answer to the question
Answer:
8 - 6 = 2
Step-by-step explanation:
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The interior angles of any triangle always sum to 180°.
In the triangle, angles C and D are labeled congruent, so the missing angle has measure
180° - 2 (6x - 5)°
This angle is supplementary to the one labeled (11x + 1)°, which means
180° = (11x + 1)° + (180° - 2 (6x - 5)°)
Solve for x :
180° = (11x + 1)° + 180° - 2 (6x - 5)°
0 = (11x + 1)° - 2 (6x - 5)°
0 = (11x)° + 1° - (12x)° + 10°
(12x - 11x)° = 1° + 10°
x° = 11°
x = 11