The area is 80 just time 10 and 2 and 4
34 x 17 (round the 2 numbers)
30 x 20
600
Also, 34 x 17 = 578, which rounds to 600
The answer is 34 and 17
Answer:
<h2>Revenue will decrease</h2>
Step-by-step explanation:
Note: the question did not provide the quantity to work with, so we will assume some values, say quantity Q= 30
Generally, it is normal for the revenue to decrease when the price of a commodity increase, this is so that buyer will have to react to adjust to the change in price.
When price increase from $50 to $60, the total revenue will decrease
let say the quantity Q1=30 , and the new quantity after price increase is Q2=20
1. The revenue PxQ before price change will be
PxQ= P1xQ1=50*30
PxQ= $1500
1. The revenue PxQ after price change will be
PxQ=P2xQ2= 60*20
P2xQ2= $1200
This clearly shows that based on the assumed data, the total revenue will drop from1500 to 1200, a total of $300 in a decrease
Answer:
a) 72.25sec
b) 6.25secs
c) after 10.5secs and 2 secs
Step-by-step explanation:
Given the height reached by the rocket expressed as;
s(t)= -4t^2 + 50t - 84
At maximum height, the velocity of the rocket is zero i.e ds/dt = 0
ds/dt = -8t + 50
0 = -8t + 50
8t = 50
t = 50/8
t = 6.25secs
Hence it will reach the maximum height after 6.25secs
To get the maximum height, you will substitute t - 6.25s into the given expression
s(t)= -4t^2 + 50t - 84
s(6.25) = -4(6.25)^2 + 50(6.25) - 84
s(6.25) = -156.25 + 312.5 - 84
s(6.25) = 72.25feet
Hence the maximum height reached by the rocket is 72.25feet
The rocket will reach the ground when s(t) = 0
Substitute into the expression
s(t)= -4t^2 + 50t - 84
0 = -4t^2 + 50t - 84
4t^2 - 50t + 84 = 0
2t^2 - 25t + 42 = 0
2t^2 - 4t - 21t + 42 = 0
2t(t-2)-21(t-2) = 0
(2t - 21) (t - 2) = 0
2t - 21 = 0 and t - 2 = 0
2t = 21 and t = 2
t = 10.5 and 2
Hence the time the rocket will reach the ground are after 10.5secs and 2 secs
Answer: is C
Step-by-step explanation:
