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Nimfa-mama [501]

3 years ago

12

NEED HELP! WILL MARK BRAINLIEST

1 answer:

ICE Princess25 [194]3 years ago

6 0

Answer:

im pretty sure its 27.

Step-by-step explanation:

if g(x) = 20 then the new problem is 20=x-7

20=x-7 . add 7 to both sides

+7=+7 . +7 cancels out the -7

27=x . <<<answer

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Use the given cost tables for the same product from two different companies to create a linear system.

alina1380 [7]

A linear function is used to represent functions that have a constant rate

$r = 33.99n +159.25$ .
$s = 37.99n +19.25$ .
Both restaurants charge at different rates

<h3></h3><h3>Linear functions</h3>

A linear function is represented as:

$y=mx + b$

Where

m represents the rate
b represents the y-intercept

<h3>The equations </h3>

For restaurant warehouse:

Start by calculating the slope (m) using:

$m = \frac{r_2 -r_1}{n_2 -n_1}$

So, we have:

$m = \frac{499.15 - 329.20}{10-5}$

$m = \frac{169.95}{5}$

$m = 33.99$

The equation is then calculated as:

$r = m(n -n_1) + r_1$

So, we have:

$r = 33.99(n -5) + 329.20$

Expand

$r = 33.99n -169.95 + 329.20$

$r = 33.99n +159.25$

For supply side:

Start by calculating the slope (m) using:

$m = \frac{s_2 -s_1}{n_2 -n_1}$

So, we have:

$m = \frac{399.15 - 209.20}{10-5}$

$m = \frac{189.95}{5}$

$m = 37.99$

The equation is then calculated as:

$s = m(n -n_1) + s_1$

So, we have:

$s = 37.99(n -5) + 209.20$

Expand

$s = 37.99n -189.95 + 209.20$

$s = 37.99n +19.25$

Read more about linear functions at:

brainly.com/question/14323743

7 0

2 years ago

.....does anyone know the answer its not 9 units

Sedbober [7]

Answer:

The answer is 10 units

5 0

4 years ago

Read 2 more answers

Which number has the greatest value?<br><br> A) |23|<br><br> B) |-24|<br><br> C) 25<br><br> D) -26

enot [183]

C 25.................

5 0

3 years ago

Read 2 more answers

Find a solution to y'(t) = te^-t satisfying the condition y(1) = 1.

Alex_Xolod [135]

Answer:

$y=-e^{-t}(t+1)+1+\frac{2}{e}$

Step-by-step explanation:

The given differential equation is

$y'(t)=te^{-t}$

It can be written as

$\frac{dy}{dt}=te^{-t}$

$dy=te^{-t}dt$

Integrate both sides.

$\int dy=\int te^{-t}dt$

Apply ILATE rule on right side. Here, t is first function and $e^{-t}$ is the second function.

$y=t\int e^{-t}-\int (\frac{d}{dt}t\int e^{-t})$

$y=-te^{-t}-\int (1\times (-e^{-t}))$ $\int e^{-x}=-e^{-x}+C$

$y=-te^{-t}+\int e^{-t}$

$y=-te^{-t}-e^{-t}+C$ .... (1)

Initial condition is y(1) = 1. It means at t=1 the value of y is 1.

$1=-(1)e^{-t}-e^{-(1)}+C$

$1=-e^{-1}-e^{-1}+C$

$1=-2e^{-1}+C$

$1=-\frac{2}{e}+C$

Add $\frac{2}{e}$ on both sides.

$1+\frac{2}{e}=C$

Substitute the value of C in equation (1).

$y=-te^{-t}-e^{-t}+1+\frac{2}{e}$

$y=-e^{-t}(t+1)+1+\frac{2}{e}$

Therefore, the solution of given initial value problem is $y=-e^{-t}(t+1)+1+\frac{2}{e}$ .

4 0

3 years ago

I need help please !!!

dolphi86 [110]

Answer:

(0, 32)

Step-by-step explanation:

The function hits the vertical line (y-axis) at it's 32 mark, and 0 is always the first coordinate of a y-intercept, so it's (0, 32).

8 0

3 years ago