3 years ago

For which distributions is the median the best measure of center?

Mathematics

1 answer:

kifflom [539]3 years ago

7 0

Answer:

I think it's C cause all the values are similar

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Shkiper50 [21]

Answer:

$\frac{x^5+y^5}{x+y}=x^4-x^3y+x^2y^2-xy^3+y^4$

Step-by-step explanation:

Given the expression

$\left(x^5+y^5\right)\div \left(x+y\right)$

$\mathrm{Apply\:factoring\:rule:\:}x^n+y^n=\left(x+y\right)\left(x^{n-1}-x^{n-2}y+\:\dots \:-\:xy^{n-2}\:+\:y^{n-1}\right)\:\quad \quad \mathrm{n\:is\:odd}$

$x^5+y^5=\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)$

$=\frac{\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)}{x+y}$

Cancel the common factor: x+y

$=x^4-x^3y+x^2y^2-xy^3+y^4$

Thus,

$\frac{x^5+y^5}{x+y}=x^4-x^3y+x^2y^2-xy^3+y^4$

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1 times 19 times 1 times 5

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The answer would be
You got it right
I wish i saw this when i needed jt too
Explanation
Absolutely

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