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Andrei [34K]
3 years ago
8

The width of Mayas poster Is 2 inches shorter than the length. The graph models the possible area (y)

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
8 0

Answer:

do you have a picture with the problem written out?

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35 POINTS WILL MARK BRAINLIEST the area of a base of a square notepad is 9 square inches. What is the length of one side of the
zimovet [89]

Answer:

3

Step-by-step explanation:

area = l^2 = 9

so,l = \sqrt{9} = 3

5 0
3 years ago
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The options are<br> 40<br> 80<br> 120<br> 140
Nataly [62]
<h2>Here we go ~ </h2>

According to given figure,

\qquad \sf  \dashrightarrow \: \angle ABC + 60° = 180°

\qquad \sf  \dashrightarrow \: \angle ABC = 180 \degree - 60 \degree

[ By linear pair ]

\qquad \sf  \dashrightarrow \: \angle ABC = 120 \degree

now, we can see that :

\qquad \sf  \dashrightarrow \: \angle ABC + \angle BAC = \angle 1

[ By Exterior angle property of Triangle ]

\qquad \sf  \dashrightarrow \: \angle 1  = 20 \degree + 120 \degree

\qquad \sf  \dashrightarrow \: \angle 1  = 140 \degree

4 0
2 years ago
Help!<br><br> Please look at the pic and help me!
inna [77]

Answer:

36

Step-by-step explanation:

equilateral triangle has all sides So,

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5 0
2 years ago
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Find the coordinates of the point 7/10 of the way from A to B
OverLord2011 [107]

Answer:

  (6.8, 1.3)

Step-by-step explanation:

<u>Given</u>:

  A(-3, -5), B(11, 4)

<u>Find</u>:

  P such that AP/AB = 7/10

<u>Solution</u>:

Using the desired relation, we have ...

  (P -A)/(B -A) = 7/10

  10(P -A) = 7(B -A) . . . . . multiply by 10(B-A)

  10P = 7B +3A . . . . . . . . add 10A to both sides

  10P = 7(11, 4) +3(-3, -5) = (77 -9, 28 -15) = (68, 13)

  P = (68, 13)/10 = (6.8, 1.3)

The point 7/10 of the way from A to B is (6.8, 1.3).

7 0
2 years ago
I need help finishing a question. I used the explanation function on the program, but it didn't specify what to do to get the fi
leva [86]

I would compute sqrt(1 + 160pi^2) first to get approximately 39.75093337

Add this to 1 and we have 40.75093337

Then divide over 2pi to get a final approximate result of 6.48571248

So x = 6.48571248 is one approximate solution

In short, I computed \frac{1+\sqrt{1+160\pi^2}}{2\pi} only focusing on the plus for now.

----------------------

If you were to compute \frac{1-\sqrt{1+160\pi^2}}{2\pi} you should get roughly -6.167402596 as your other solution. Each solution can then be plugged into the original equation to check if you get 0 or not. You likely won't land exactly on 0 but you'll get close enough.

6 0
3 years ago
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