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MatroZZZ [7]
2 years ago
10

I need to find the equation of the line

Mathematics
1 answer:
Delvig [45]2 years ago
8 0

Answer:

y= -3x + 7

That is the answer.

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Given lines L1 and L2 and L1 = (1-a)x-y and L2= 6x+ay =9 find the value of a if L1 and L2 are parallel then L1 and L2 are perpen
sammy [17]

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3people equally share 4 oranges. How many oranges<br>does each person get?​
Nutka1998 [239]

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1\frac{1}{3}

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50 decreased by twice a number
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50-2n

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2 years ago
Please help i’m really struggling!!!!
Gnoma [55]

x-intercepts are points of the form (x, 0), and y-intercepts are points of the form (0, y).

You find the x-intercepts by solving for x such that y = f(x) = 0:

x^3-9x^2+20x-12=0

You know x - 6 is a factor of f(x), which means x = 6 is a solution to the above equation, and that means that (6, 0) is one x-intercept.

You can find the other two by dividing f(x) by x - 6 (i.e. further factorizing f(x)).

\dfrac{x^3-9x^2+20x-12}{x-6}=x^2-3x+2=(x-2)(x-1)

So we have

x^3-9x^2+20x-12=(x-6)(x-2)(x-1)=0\implies x=6,x=2,x=1

and this means the x-intercepts are (6, 0), (2, 0) and (1, 0).

The y-intercept is easier to find; set x = 0, then solve for y = f(0):

y=0^3-9\cdot0^2+20\cdot0-12=-12

and so the y-intercept is (0, -12).

6 0
3 years ago
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