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anyanavicka [17]
3 years ago
12

A line extends infinitely far in two directions. A. True B. False

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
7 0
Yes, a line does extend infinitely far in two directions, so it is true.
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MARK ME AS A BRAINLIST..........

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Find the derivative of f(x) = 8 divided by x at x = -1.<br><br> 4<br> 0<br> 8<br> -8
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Help will mark brainlist if it correct If each edge of a cube is increased by 2 inches, the
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Answer:

D. sum of these edges is increased by 24 inches -- True

Step-by-step explanation:

Given a cube and its edge is increased by 2 inches.

To study the effect of this increase in the Volume, area of each face, diagonal and sum of edges.

Solution:

Let the side of original cube = a inches.

Formula for volume of cube:

V =side^3 = a^3

If the side is increased by 2 inches, the side becomes (a+2) inches.

So, new volume, V' = (a+2)^3

Using the formula:

(x+y)^3 =x^3+y^3+3xy(x+y)

V' = (a+2)^3 = a^3+8+3\times 2 \times a(a+2)=a^3+8+6a(a+2)

So, V' = V + 8+6a(a+2)

Volume increased by 8+6a(a+2) [which is not equal to 8]

So, statement is false:

A. volume is increased by 8 cubic inches  -- False

Each face in a cube is a square.

Area of each face, A = side^2 = a^2

New area, A' = (a+2)^2

Using the formula: (x+y)^2 =x^2+y^2+2xy

A' = a^2+4+4a

Area increased by 4+4a [which is not equal to 4 sq inches]

B. area of each face is increased by 4 square inches -- False

Diagonal of each face = a\sqrt2

Increase of 2 in the edge:

New diagonal = (a+2)\sqrt2 = a\sqrt2+2\sqrt2

So, increase of 2\sqrt2 not 2.

C. diagonals of each face is increased by 2 inches -- False

There are 12 number of edges in a square.

So sum of all 12 edges  = 12a

When edge is increased by 2, sum of all edges = 12(a+2) = 12a + <em>24</em>

An increase of 24.

D. sum of these edges is increased by 24 inches -- True

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80% of salmon pass through a single dam unharmed. By what percent does the number of salmon decrease when passing through a sing
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WILL GIVE BRAINLIEST!!!!! PLS HELP ASAP!!!! 100 POINTS!!!!!!
PSYCHO15rus [73]

Answer:

the linear function gives us the points

(0,3)

(4,0)

(8,-3)

find the equation

hm

find slope

(y2-y1)/(x2-x1)

for (0,3) and (4,0)

slope=(0-3)/(4-0)=-3/4

y=-3/4x+b

given

(0,3)

y=-3/4x+3

so sub -3/4x+3 for y in other equation

(-3/4x+3)^2+x^2=4

expand

9/2x^2-9/2x+9+x^2=4

11/2x^2-9/2x+9=4

times 2 both sides

11x^2-9x+18=8

minus 8 both sides

11x^2-9x+10=0

factor

or use quadratic formula

for

ax^2+bx+c=0

x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

2a

−b+/−

b

2

−4ac

11x^2-9x+10=0

x=\frac{-(-9)+/- \sqrt{(-9)^2-4(11)(10)} }{2(11)}

2(11)

−(−9)+/−

(−9)

2

−4(11)(10)

x=\frac{9+/- \sqrt{81-440} }{22}

22

9+/−

81−440

x=\frac{9+/- \sqrt{-359} }{22}

22

9+/−

−359

we see we have no real roots

there are no intersection points

#Carry on learning

#Correct me if I'm wrong

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3 years ago
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