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Lera25 [3.4K]
3 years ago
7

Find an integer, x, such that 2, 4, and x represent the lengths of the sides of an obtuse triangle.

Mathematics
1 answer:
Tatiana [17]3 years ago
5 0

Answer:

A

Step-by-step explanation:

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Multiply the sum of X and Y by 5 and divide the result by the product of two and a​
kvv77 [185]

Answer:

\frac{5(x+y)}{2a} or you could write it as 5(x+Y) ÷ 2a

Step-by-step explanation:

So this is a question that kind of uses spoken words rather than numbers and it involves PEMDAS (if you haven't gotten to PEMDAS yet, don't worry about it, it's ok, it's easy). PEMDAS is simply an acronym for Parenthesis, Exponent, Multiply, Divide, Add, Subtract. Its the order in wwhich you do more complicaterd math problems.

Lets break apart the question:

- We have the sum of x and y, we just write that as x+y

- We have that sum multiplied by 5, we have the sum from the step above, now we'll multiply that by 5. 5(x+y) parenthesis means multiply what is outside with what is inside.

- We have the product (multiply) of 2 and a, 2 times a = 2a.

- We divide the x, y, and 5 term with the 2, a term. Take the first part 5(x+y) and divide it by the second part 2a.

6 0
3 years ago
The probability of drawing a heart from a standard deck of 52 playing cards is 1 4 . The probability of drawing a face card from
hoa [83]
We need Probability of drawing a heart Or drawing a face card other than a heart. 

This is 1/4 + 9/52  = 11/26
C is the correct choice.
8 0
3 years ago
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There were a total of 24 basketball games in the
dedylja [7]

Answer:

6 Games each Month

Step-by-step explanation:

Total Basketball Games = 24

Months = 4

Each Month Basket Ball Games = Total Basketball Games / Months

Each Month Basket Ball Games = 24 / 4

Each Month Basket Ball Games = 6

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3 years ago
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Calculate |m| if m=21-72i. Round off answer to nearest hundred
arlik [135]

Answer:

n6666667900087474455

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PLEASE HELP HELP ASAP ASAPP WILL GIVE 100 POINTS AND BRAINLEST! PLUS MY THANKS AND ADMIRATION PLEASE PLEASE!!
tatyana61 [14]

Answer:

First Picture ⇒ [B] <em>a = -2, b = 1, and c = -5</em>

<em>Second Picture ⇒ First step: Identify a = 1, b = 3, c = -4</em>

<em>                           </em>x=\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \left(-4\right)}}{2\cdot \:1}

<em>                              </em>x=\frac{-3\pm 5\sqrt{25}}{2}

                           x=\frac{-3\pm \:5}{2}

                        x=\frac{-3+5}{2},\:x=\frac{-3-5}{2\c}

Third Picture ⇒ Missing Info

Fourth Picture ⇒ [A] x=-\frac{5}{2},\:x=-3

Fifth Picture ⇒ x=\frac{5\pm\sqrt{1} }{2}

Step-by-step explanation:

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>Identify the a,b, and c-values for this equation:</em>

<em>y = -2x²  + x -5  </em>

<em>Quadratic Formula:</em>

<em>ax²+bx+c=0</em>

<em>−2x²+1x−5=0</em>

<em>a = -2, b = 1, and c = -5</em>

<em>-------------------------------------------------------------------------------------------------------------</em>

Order the steps for solving this equation using the quadratic formula.

x<em>²  + 3x - 4 = 0</em>

<em>Solving to see what are the steps:</em>

<em>First step: Identify a = 1, b = 3, c = -4</em>

<em />x=\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \left(-4\right)}}{2\cdot \:1}

x=\frac{-3\pm 5\sqrt{25}}{2}

x=\frac{-3\pm \:5}{2}

x_1=\frac{-3+5}{2\cdot \:1},\:x_2=\frac{-3-5}{2\cdot \:1}

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>Use the quadratic formula to find the solution set for 2x² + 15 = -11x.</em>

<em>Add 11x to both sides:</em>

<em>2x² + 15+11x = -11x+11x</em>

<em>Simplify</em>

<em>2x² + 11x+15 = 0</em>

<em>Now solve with quadratic formula..</em>

<em />x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:2\cdot \:15}}{2\cdot \:2}

x_{1,\:2}=\frac{-11\pm \:1}{2\cdot \:2}

x_1=\frac{-11+1}{2\cdot \:2},\:x_2=\frac{-11-1}{2\cdot \:2}

x=-\frac{5}{2},\:x=-3

Hence, [A] x=-\frac{5}{2},\:x=-3

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>Suppose you are solving a quadratic equation and this is your work so far...</em>

<em>x  ²  - 5x + 6 = 0</em>

<em>Thus, we have:</em>

<em />x=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:1\cdot \:6}}{2\cdot \:1}

x=\frac{-\left(-5\right)\pm \:1}{2\cdot \:1}

x=\frac{5\pm\sqrt{1} }{2}

x_1=\frac{-\left(-5\right)+1}{2\cdot \:1},\:x_2=\frac{-\left(-5\right)-1}{2\cdot \:1}

x=3,x=2

<em>-------------------------------------------------------------------------------------------------------------</em>

<u><em>Kavinsky</em></u>

6 0
2 years ago
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