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horsena [70]
2 years ago
5

Help me please !! thank you!

Mathematics
1 answer:
mr Goodwill [35]2 years ago
8 0
This what got , hope it helps

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Plan A charges $20 a month with a $10 sign up fee. Plan B changes a $20 sign up fee but $15 each month.
prohojiy [21]

Answer:

X- 12 months, Y- 450 in total

Step-by-step explanation:

unsure what you would want for the answer to be but,

if plan a were to charge you for a year 20 x 12 would be 240 dollars a year + 10 would be 250 the total cost.

plan b, same thing 15 x 12 is 180 + 20 which would be 200 the total cost.

if you wanted both months added together, it would be 420 since x was 12.

and both sign up fees would be 30 dollars, if they needed a sign up fee for each month as well, it would be 360 per.

the total cost for all of plan a and b together would be 450 because you added the 30 dollar fee to the total of each plan.

P.S.- sorry if its long

7 0
3 years ago
PLEASE HELP, I don’t understand it at all!!
netineya [11]

Answer:

15km

Step-by-step explanation:

Use the Pythagorean Theorem

a²+b²=c²

9²+12²=c²

81+144=c²

225=c²

Square root both sides

c= 15km

7 0
2 years ago
Read 2 more answers
Ik I don't normally ask actual questions but how do you multiply radicals T^T pls
balandron [24]

Answer:

I think it will become an exponet

Step-by-step explanation:

you can't times letters

7 0
2 years ago
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Calcula un numero sabiendo que la suma de sus dos cifras es 10 y que si invertimos el orden de dichas cifras, el numero obtenido
emmainna [20.7K]

como es eso entonses me enseñaron mal a mi o que

4 0
3 years ago
Criterion: Identify IV, DV, and hypotheses and evaluate the null hypothesis for an independent samples t test. Data: Use the inf
Papessa [141]

The table is missing in the question. The table is provided here :

Group 1        Group 2

 34.86            64.14      mean

 21.99            20.46      standard deviation

  7                    7                n

Solution :

a). The IV or independent variable = Group 1

    The DV or the dependent variable = Group 2

b).

  $H_0: \mu_1 = \mu_2$

  $H_a:\mu_1 < \mu_2$

  Therefore,   $t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{S_2^2}{n_2}}}$

$t = \frac{34.86 - 64.14}{\sqrt{\frac{21.99^2}{7}+\frac{20.46^2}{7}}}$

t = -2.579143

Now,   $df = min(n_1 - 1, n_2 - 1)$

           df = 7 - 1

               = 6

Therefore the value of p :

  $=T.DIST(-2.579143,6,TRUE)$

 = 0.020908803

The p value is 0.0209

$p< 0.05$

So we reject the null hypothesis and conclude that $\mu_1 < \mu_2$

7 0
3 years ago
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