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masha68 [24]
3 years ago
15

If you place a 17 foot ladder against the top of a 8 foot building how many feet will the bottom of the ladder be from the botto

m of the building
Mathematics
2 answers:
KatRina [158]3 years ago
7 0
9 because if you subtract 17 from 8 you will get 9 I hope this works :)
Allushta [10]3 years ago
3 0

Answer:

15 ft

Step-by-step explanation:

1. Draw a triangle with a right angle.

2. Label all sides: A being the straight line which is standing vertically, B which is the base or the line which lays horizontally, and C will be the longest line on the triangle.

3. Make the C to be 17 ft.

4. Mark A as 8 ft.

5. Now use the Pythagorean Theorem: a^{2}+b^{2}=c^{2}

   8^{2} +b^{2} =17^{2}

6. Solve the equation:

8^{2}+b^{2}=17^{2}\\64+b^{2}=289\\b^{2}=225\\\sqrt{b^{2}}=\sqrt{225}\\b=15

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3 0
2 years ago
ANSWER ASAP RIGHT ANSWER = BRAINLIST 100 POINTS
ale4655 [162]

Answer:

-6.75

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3 years ago
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blsea [12.9K]

I can't see the whole pic...

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3 0
2 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
Solve for d.<br><br> 13d + 4 = 43<br><br> A.3<br><br> B.13<br><br> C.39<br><br> D.None of the above
sergejj [24]
Answer is A
Because 43-4=39
39/13=3
6 0
3 years ago
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