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3 years ago

Help.....................

Mathematics

1 answer:

Yakvenalex [24]3 years ago

7 0

Answer:

Translation

Step-by-step explanation:

In a translation, every point of the object must be moved in the same direction and for the same distance. PLS MARK MY ANSWER AS THE BRAINLIEST!! PLS

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Simplify: 3 + 2s - 4 + 3s

Aliun [14]

Answer:

-1 + 5s

Explanation:

3 - 4 = -1

2s + 3s = 5s

3 0

3 years ago

Read 2 more answers

7. Use the Division Property of Equality to complete the following statement. (1 point)

djyliett [7]

For this case we have the following equation:

$5x = 2y$

To find the value of "x", we use the division equality property, that is, we divide by 5 on both sides of the equation:

$\frac {5x} {5} = \frac {2y} {5}\\x = \frac {2} {5} y$

Thus, using the mentioned property we have to: $x = \frac {2} {5}y$

Answer:

$x = \frac {2} {5} y$

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3 years ago

One Step Equation. One Step Subtraction. 1) x - 2 = 10 2) x -12 = 24 3) x - 5 = 4

gtnhenbr [62]

Answer:

x= 9

Step-by-step explanation:

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3 years ago

The Hyperbolic Sine (sinh(x)) and Hyperbolic Cosine (cosh(x)) functions are defined as such: sin h(x) = e^x - e^-x/2 cosh(x) = e

labwork [276]

Answer:

y-incercepts:

sinh(x):0, cosh(x)=1

Limits:

positive infinity: sinh(x): infinity, cosh(x): infinity

negative infinity: sinh(x): - infinity, cosh(x): infinity

Step-by-step explanation:

We are given that

$\sinh(x)=\frac{e^{x}-e^{-x}}{2}$

$\cosh(x)=\frac{e^{x}+e^{-x}}{2}$

To find out the y-incerpt of a function, we just need to replace x by 0. Recall that $e^{0}=1$ . Then,

$\sinh(0) = \frac{1-1}{2}=0$

$\cosh(0) = \frac{1+1}{2}=1$

For the end behavior, recall the following:

$\lim_{x\to \infty}e^{x} = \infty, \lim_{x\to \infty}e^{-x} = 0$

$\lim_{x\to -\infty}e^{x} = 0, \lim_{x\to -\infty}e^{-x} = \infty$

Using the properties of limits, we have that

$\lim_{x\to \infty} \sinh(x) =\frac{1}{2}(\lim_{x\to \infty}e^{x}-\lim_{x\to \infty}e^{-x})=(\infty -0) = \infty$

$\lim_{x\to \infty} \cosh(x) =\frac{1}{2}(\lim_{x\to \infty}e^{x}+\lim_{x\to \infty}e^{-x}) =(\infty -0)= \infty$

$\lim_{x\to -\infty} \sinh(x) =\frac{1}{2}(\lim_{x\to -\infty}e^{x}-\lim_{x\to -\infty}e^{-x}) = (0-\infty)=-\infty$

$\lim_{x\to -\infty} \cosh(x) =\frac{1}{2}(\lim_{x\to -\infty}e^{x}+\lim_{x\to -\infty}e^{-x}) =(0+\infty)= \infty$

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3 years ago

For a scale of 1cm: 12km what is the actual length represented by 1.7 cm

madreJ [45]

It would be 20.4 km because if 1cm is 12km then you just have to multiply 1.7 x 12 = 20.4.

7 0

3 years ago