What is the solution to the following system?

Mathematics

2 answers:

babunello [35]2 years ago

6 0

The solution to the system is (2, 1, 0).

Anit [1.1K]2 years ago

4 0

Answer:

The solution to the system is (2, 1, 0).

Step-by-step explanation:

You might be interested in

If x and y are odd numbers such that 10<x<y14, what is value of x+y?

wel

I will suppose that your queation is 10<x<y<14
there are only two odd between 10 and 14
which are 11 and 13
since x is smaller than y
x=11 and y=13
there sum will be x+y=11+13=24

5 0

3 years ago

How do you work out this equation

Gnom [1K]

Answer:

x is equal to negative one, and y is equal to negative four.

Step-by-step explanation:

You can do this by solving one of the equations by either x or y, then substituting it into the other. Let's solve the second one for y:

$2y = 3x - 5\\y = \frac{3x - 5}{2}$

Now we'll substitute that into the first equation:

$9x - 2y = -1\\9x - 2(\frac{3x - 5}{2}) = -1\\9x - 3x + 5 = -1\\6x + 5 = -1\\6x = -6\\x = -1$

So we now know that x is equal to -1. We can simply substitute that into one of the original equations to find y:

$2y = 3x - 5\\2y = 3(-1) - 5\\2y = -3 - 5\\2y = -8\\y = -4$

We now know that x is equal to -1, and y is equal to -4. We can also check our answer by plugging that -4 into the other equation, and see if we still get -1:

$9x - 2y = -1\\9x - 2(-4) = -1\\9x + 8 = -1\\9x = -1 - 8\\9x = -9\\x = -1$