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3 years ago

What is the solution to the following system?

Mathematics

2 answers:

babunello [35]3 years ago

6 0

The solution to the system is (2, 1, 0).

Anit [1.1K]3 years ago

4 0

Answer:

The solution to the system is (2, 1, 0).

Step-by-step explanation:

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Find an equation for the inverse of the following relation.<br><br> y=12x-3

vovikov84 [41]

<h3>Answer:</h3>

<em>Your answer would be y=x+3/12</em>

<h3>Step-by-step explanation:</h3>

Firstly, you'll switch sides of the equation.

Next, add 3 to both sides.

Simplify it.

Then, divide both sides by 12.

Simplify once more.

12y/12 = x/12 + 3/12 --- y= x+3/12

<u>y=x+3/12 would be your answer.</u>

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3 years ago

your trying to save up for a trip to hawaii. Your trying to budget for a hotel, and you found a really nice one for 1,200. And t

stepladder [879]

Answer:

4800 good luck

Step-by-step explanation:

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3 years ago

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Dan earns $8.25 an hour and works 20 hours a week. How much will he earn in three weeks?

maksim [4K]

Okay. So first 8.25 * 20 = 165. Then you multiply 165 by 3 (165*3). 165 * 3 = 495.
Dan will earn $495 in three weeks.

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4 years ago

Super Bowl XLVI was played between the New York Giants and the New England Patriots in Indianapolis. Due to a decade-long rivalr

Diano4ka-milaya [45]

Answer:

Probability that from a sample of 200 Indianapolis residents, fewer than 170 were rooting for the Giants in Super Bowl XLVI is 0.02385.

Step-by-step explanation:

We are given that Due to a decade-long rivalry between the Patriots and the city's own team, the Colts, most Indianapolis residents were rooting heartily for the Giants. Suppose that 90% of Indianapolis residents wanted the Giants to beat the Patriots.

Let p = % of Indianapolis residents wanted the Giants to beat the Patriots = 90%

The z-score probability distribution for proportion is given by;

Z = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = % of Indianapolis residents who were rooting for the Giants in Super Bowl XLVI in a sample of 200 residents = $\frac{170}{200}$ = 0.85

n = sample of residents = 200

So, probability that from a sample of 200 Indianapolis residents, fewer than 170 were rooting for the Giants in Super Bowl XLVI is given by = P( $\hat p$ < 0.85)

P( $\hat p$ < 0.85) = P( $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < $\frac{0.85-0.90}{\sqrt{\frac{0.85(1-0.85)}{200} } }$ ) = P(Z < -1.98) = 1 - P(Z $\leq$ 1.98)