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3 years ago

Write the equation of a line perpendicular to y=3x-2 through the point (-5,8).

Mathematics

1 answer:

TEA [102]3 years ago

6 0

Answer:

y=-1/3x +29/3

Step-by-step explanation

We know that the line perpendicular to a slope of 3 is it's opposite reciprocal. So the slope is -1/3. Substitute -5 as X and 8 as Y so you get:

8= -5/3x +b.

B= 29/3

That's your answer.

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What is the value of x? There is isosceles triangle. The measure of angle which is between two congruent sides is (6x+10⁰). The

max2010maxim [7]

<h3><u>Answer</u><u>:</u><u>-</u></h3>

x=17

<h3><u>step-by</u><u>-</u><u>step</u><u> </u><u>Explanation</u><u>:</u><u>-</u></h3>

${\boxed{\quad\:\mapsto\rm Firstly\:Let's\:understand\:the\:concept:-}}$

<h3 />

This is a isosceles triangle. As it is a triangle we can apply sum theory. we have to take the sum of given unknown polynomials as 180° .Then by solving it we can find the value of x.

<h3><u>Solution</u><u>:</u><u>-</u></h3>

Given angles

(6x+10°)
(x+17°)
(4x-34)°

According to sum theory

${\boxed{\sf The \:sum\:of\:angles=180°}}$

Substitute the values

$\qquad \quad{:}\longmapsto\tt (6x+10)+(x+17)+(4x-34)=180$

Remove brackets

$\qquad \quad{:}\longmapsto\tt 6x+10+x+17+4x-34=180$

Together like polynomials and constants

$\qquad \quad{:}\longmapsto\tt 6x+x+4x+10+17-34=180$

$\qquad \quad{:}\longmapsto\tt 11x-7=180$

Interchange sides

$\qquad \quad{:}\longmapsto\tt 11x=180+7$

$\qquad \quad{:}\longmapsto\tt 11x=187$

$\qquad \quad{:}\longmapsto\tt x=\cancel{\dfrac{187}{11}}$

Simplify

$\qquad \quad{:}\longmapsto\tt x=17$

$\therefore\sf The \:value\:of\:x\;is\:17.$

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3 years ago