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Likurg_2 [28]
3 years ago
5

Write the equation of a line perpendicular to y=3x-2 through the point (-5,8).

Mathematics
1 answer:
TEA [102]3 years ago
6 0

Answer:

y=-1/3x +29/3

Step-by-step explanation

We know that the line perpendicular to a slope of 3 is it's opposite reciprocal. So the slope is -1/3. Substitute -5 as X and 8 as Y so you get:

8= -5/3x +b.

B= 29/3

That's your answer.

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