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3 years ago

Get free points by answering 100*100 please help asap

Mathematics

2 answers:

andreev551 [17]3 years ago

8 0

Answer:10,000

Step-by-step explanation: 100x100

1x1 equal 1 then just add 4 zeros

alexandr402 [8]3 years ago

8 0

The answer is 10,000.
You get this answer because you add the four zeros.

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Gabby assumed she could sell 45 boxes of cookies by Friday, but she only sold 26 boxes. What was Gabby's percent error?

Agata [3.3K]

Answer:

73.07%

Step-by-step explanation:

Given that,

Actual value of sold cookies = 26

Assumed value of sold cookies = 45

We need to find Gabby's percent error. The percentage error in a value is given by :

Error = ](Assumed value - Actual value)/Actual value]× 100

So,

$\%=\dfrac{45-26}{26}\times 100\\\\=73.07\%$

So, Gabby's percent error is equal to 73.07%.

4 0

3 years ago

8x+y=300

Bond [772]

D. The elevator takes 37.5 seconds to move down to the lobby.

8x+y=300

y= 300-8x
y= 300 - 8 (37.5)

y = 300-300
y = 0

wheb y =0 that means that the height is 0

5 0

3 years ago

La suma de dos números es igual a 16 y su diferencia es –4. ¿cuál es el número menor? *

blagie [28]

Explicación paso a paso:

a+b=16 +

a-b=-4

----------

2a=12

a=6

b=10

el menor vale 6

<h2>y porfavor branliest! :)</h2>

8 0

3 years ago

-48=-8x+8 solve the equation

aleksley [76]

Answer:

x=7

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS

Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

$a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\$

With respect to reference angle A, we have:

opposite side = a = 4
adjacent side = b = $\sqrt{33}$
hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\$

Then cosine which is adjacent over hypotenuse

$\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\$

Tangent is the ratio of opposite over adjacent

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\$

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

cosecant, abbreviated as csc, is the reciprocal of sine
secant, abbreviated as sec, is the reciprocal of cosine
cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

$\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{ ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

------------------------------------------------------

Summary:

The missing side is $b = \sqrt{33}$

The 6 trig functions have these results

$\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0

1 year ago