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romanna [79]
3 years ago
5

Answer this question please answerWhole number 34 to 77​

Mathematics
2 answers:
alexira [117]3 years ago
4 0
42 is the right one for this problem have a good day
givi [52]3 years ago
3 0

There are 42 whole numbers between 34 to 77

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What is the first step in silving this equation?<br> 3n - 4 = -2 + 2n
Pie

Answer:

3n - 4 =  - 2 + 2n \\  or \: 3n - 2n =  - 2 + 4 \\ or \: n \: =  + 2 \\ or \: n = 2 \\ therefore \: n = 2

<h3>The Answer of this question is 2.</h3>

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Sebastian swam laps every day in the community swimming pool. He swam 45 minutes each day, five days each week, for 12 weeks. In
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3 years ago
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What is the answer to this equation
julia-pushkina [17]

Answer:

x = - \frac{494}{3} = - 164\frac{2}{3}

Step-by-step explanation:

75 + \frac{3}{8} x = 13\frac{1}{4}\\\\75 + \frac{3}{8} x = \frac{53}{4}\\\\\frac{3}{8}x = \frac{53}{ 4} - 75\\\\\frac{3}{8}x = \frac{53-300}{4}\\\\\frac{3}{8}x = - \frac{247}{4}\\\\x = -\frac{247 \times 8}{4 \times 3} \\\\x = -\frac{494}{3}

6 0
2 years ago
How do I solve this
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\bf \cfrac{x+2}{x^2+6x-7}    so, that function is "defined", ok, what values of "x" are not in the domain, namely, what values can "x" take on and not make the function "undefined", well,  you know, if we end up with a 0 at the denominator, like   \bf \cfrac{x+2}{0}    then, we'd have an "undefined" expression...so... any values of "x" that make the denominator 0, are not really the ones we want, and thus they'd be excluded from the domain.


so, hmm which are those? let's check, let's set the denominator to 0, and solve for "x".

\bf x^2+6x-7=0\implies (x+7)(x-1)=0\implies x=&#10;\begin{cases}&#10;-7\\&#10;1&#10;\end{cases}&#10;\\\\\\&#10;\textit{let's check, } x=-7\quad \cfrac{(-7)+2}{(-7)^2+6(-7)-7}\implies \cfrac{-5}{49-42-7}\implies \cfrac{-5}{0}&#10;\\\\\\&#10;x=1\quad \cfrac{(1)+2}{(1)^2+6(1)-7}\implies \cfrac{3}{1+6-7}\implies \cfrac{-3}{0}
7 0
3 years ago
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