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cestrela7 [59]
3 years ago
7

With milk sales sagging of late, The Milk Processor Education Program (MPEP) decided to move on from the famous "Got Milk" ad sl

ogan in favor of a new one, "Milk Life." The new tagline emphasizes milk's nutritional benefits, including its protein content.
MPEP began collecting data on the number of gallons of milk households consumed weekly (in millions), weekly price per gallon, and weekly expenditures on milk advertising (in hundreds of dollars) for the period following the launch of the new campaign. These data, in forms to estimate both a linear model and log-linear model, are available via the link below. Use these data to perform two regressions; a linear regression and a log-linear regression.
Suppose that the weekly price of milk is $3.40 per gallon and MPEP decides to ramp up weekly advertising by 35 percent to $150 (in hundreds). Use the best-fitting regression model to estimate the weekly quantity of milk consumed after this advertising increase.

Linear Model Log-Linear Model
Q P A lnQ lnP lnA
4.76 2.46 472.68 1.56 0.90 6.16
0.90 4.28 326.41 -0.10 1.45 5.79
1.74 3.72 357.36 0.55 1.31 5.88
0.96 4.20 475.82 -0.04 1.43 6.17
2.38 4.14 494.25 0.87 1.42 6.20
1.28 4.59 458.62 0.25 1.52 6.13
2.86 3.30 421.67 1.05 1.19 6.04
1.87 4.34 534.85 0.63 1.47 6.28
2.19 3.31 524.75 0.78 1.20 6.26
1.38 3.35 370.35 0.32 1.21 5.91
0.21 4.53 420.16 -1.54 1.51 6.04
3.55 2.63 333.79 1.27 0.97 5.81
2.44 4.40 437.32 0.89 1.48 6.08
1.94 4.36 442.70 0.66 1.47 6.09
2.50 3.24 375.67 0.91 1.18 5.93
2.92 3.45 546.36 1.07 1.24 6.30
4.94 2.97 391.17 1.60 1.09 5.97
2.14 3.22 498.00 0.76 1.17 6.21
3.89 3.34 530.17 1.36 1.20 6.27
6.91 2.24 527.36 1.93 0.81 6.27
3.41 4.04 440.93 1.23 1.40 6.09
1.16 4.10 480.35 0.15 1.41 6.17
1.60 3.99 404.91 0.47 1.38 6.00
4.09 3.22 512.00 1.41 1.17 6.24
2.69 2.98 346.29 0.99 1.09 5.85
2.41 4.30 383.47 0.88 1.46 5.95
2.25 2.84 434.26 0.81 1.04 6.07
2.48 3.96 548.37 0.91 1.38 6.31
3.79 2.49 357.71 1.33 0.91 5.88
3.33 3.29 445.73 1.20 1.19 6.10
2.61 4.02 524.55 0.96 1.39 6.26
2.40 4.05 487.87 0.88 1.40 6.19
3.92 2.46 343.13 1.37 0.90 5.84
3.42 3.45 353.81 1.23 1.24 5.87
0.80 3.40 334.47 -0.23 1.22 5.81
5.79 2.95 330.57 1.76 1.08 5.80
3.58 2.69 363.91 1.28 0.99 5.90
1.58 3.79 383.71 0.46 1.33 5.95
1.14 3.37 430.37 0.13 1.21 6.06
1.04 4.64 501.84 0.04 1.54 6.22
4.88 2.66 447.12 1.59 0.98 6.10
4.31 2.25 404.38 1.46 0.81 6.00
2.23 3.94 449.29 0.80 1.37 6.11
1.38 4.42 327.99 0.32 1.49 5.79
1.62 3.13 332.39 0.49 1.14 5.81
1.38 4.45 450.16 0.33 1.49 6.11
6.20 2.38 467.40 1.82 0.87 6.15
4.17 3.69 528.60 1.43 1.31 6.27
4.08 4.02 533.73 1.41 1.39 6.28
0.08 4.30 355.81 -2.55 1.46 5.87
3.82 2.80 462.42 1.34 1.03 6.14
1.17 4.51 549.78 0.16 1.51 6.31
3.26 2.42 366.63 1.18 0.88 5.90
2.44 4.37 429.74 0.89 1.47 6.06
4.16 2.53 399.57 1.42 0.93 5.99
2.63 3.63 521.95 0.97 1.29 6.26
4.94 2.80 356.59 1.60 1.03 5.88
1.84 4.36 416.24 0.61 1.47 6.03
4.71 3.12 435.99 1.55 1.14 6.08
6.46 2.40 464.62 1.87 0.87 6.14
2.79 3.51 353.37 1.03 1.25 5.87
4.09 3.07 425.12 1.41 1.12 6.05
4.76 2.32 481.72 1.56 0.84 6.18
3.05 3.45 376.30 1.12 1.24 5.93
0.87 4.44 536.86 -0.13 1.49 6.29
3.12 2.50 493.52 1.14 0.92 6.20
1.34 3.11 454.69 0.29 1.13 6.12
1.93 3.24 487.07 0.66 1.17 6.19
1.64 2.87 461.69 0.50 1.05 6.13
4.39 2.97 410.84 1.48 1.09 6.02
5.76 2.33 480.66 1.75 0.84 6.18
4.40 2.82 381.62 1.48 1.04 5.94
6.22 3.14 456.97 1.83 1.14 6.12
1.10 3.89 461.39 0.09 1.36 6.13
4.12 2.67 430.43 1.42 0.98 6.06
5.40 2.73 438.53 1.69 1.01 6.08
2.75 4.52 336.00 1.01 1.51 5.82
5.12 2.28 519.90 1.63 0.83 6.25
3.94 3.25 536.25 1.37 1.18 6.28
5.69 2.18 439.75 1.74 0.78 6.09
0.44 4.27 352.57 -0.82 1.45 5.87
1.89 3.62 397.69 0.64 1.29 5.99
4.02 3.32 345.17 1.39 1.20 5.84
3.70 3.43 507.56 1.31 1.23 6.23
3.26 2.43 330.67 1.18 0.89 5.80
2.98 2.97 433.20 1.09 1.09 6.07
2.09 4.32 462.14 0.74 1.46 6.14
5.68 2.25 515.33 1.74 0.81 6.24
4.33 2.65 508.14 1.47 0.98 6.23
4.97 3.63 510.41 1.60 1.29 6.24
2.89 3.60 343.16 1.06 1.28 5.84
2.25 3.37 365.82 0.81 1.22 5.90
0.17 3.77 425.56 -1.79 1.33 6.05
3.96 2.87 347.36 1.38 1.06 5.85
4.08 2.97 326.06 1.40 1.09 5.79
3.49 3.94 527.12 1.25 1.37 6.27
4.21 4.10 475.28 1.44 1.41 6.16
2.25 4.09 475.69 0.81 1.41 6.16
2.40 3.93 536.42 0.88 1.37 6.28
1.61 4.10 325.89 0.48 1.41 5.79
Business
1 answer:
aniked [119]3 years ago
5 0

Answer:

bggggggggggdgfdfgfghghkj

Explanation:

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Assuming that a market research study will answer important questions and reduce uncertainty associated with the proposed projec
sesenic [268]

Answer:

C. Is top management committed to the study?

Explanation:

Yes, market research is very important for the organisations which can help them in finding new trends and patterns in their consumers, they can find out what are products which they need to launch further, which products are not performing well but the main question before starting the research process is that each and every single person of the organisation should take part in the whole process particularly the top level management should be agrees upon and committed to it otherwise the whole process will go in vain. Because when the top level will be committed, they not only by proving the resources needed for the research but also they will be happily implementing the research findings for the betterment of the organisation. Therefore, top management should be committed otherwise it will just be waste of time and efforts.

3 0
3 years ago
On January 1, 2014, Evers Company purchased the following machine for use in its production process:
iren2701 [21]

Answer:

a) Calculate the amount of depreciation expense that Evers should record each year of its useful life under the following assumptions. Show your workings.

(1) Straight-line method

depreciable value = $180,000 - $10,000 = $170,000 / 4 = $42,500 per year (same for each year)

(2) Double declining balance method

depreciation expense year 2014 = $180,000 x 1/4 x 2 = $90,000

depreciation expense year 2015 = $90,000 x 1/4 x 2 = $45,000

depreciation expense year 2016 = $45,000 x 1/4 x 2 = $22,500

depreciation expense year 2017 = $22,500

(3) Units-of-activity method and estimates that the useful life of machine is 125,000 units. Actual usage is as follows: 2014, 45,000 units; 2015, 35,000 units; 2016, 25,000 units; 2017, 20,000 units.

depreciation expense per unit = $170,000 / 125,000 units = $1.36

depreciation expense year 2014 = $1.36 x 45,000 = $61,200

depreciation expense year 2015 = $1.36 x 35,000 = $47,600

depreciation expense year 2016 = $1.36 x 25,000 = $34,000

depreciation expense year 2017 = $1.36 x 20,000 = $27,200

b) Which method used to calculate depreciation reports the highest amount of depreciation expense in year 1?

double declining balance

The highest in year 4?

straight line method

The highest total amount over the 4-year period?

double declining balance

5 0
3 years ago
You and the HR manager, along with suggestions from the branch manager, must determine if background checks on all employees are
sergey [27]

Answer:

Terminate his employment

Explanation:

Based on the fact and information, Tibbits should be discharged from employment for his failure to disclose this relevant conviction. As a convicted offender, he is considered in the eyes of the  law to be high-risk and should not be allowed to enter unsuspecting clients’ homes.  It would be the company's liability if he acts non professionally and inappropriately at a jobsite.

7 0
2 years ago
 Because of its importance in summarizing your strategy, the Introduction and Overview of your business plan should be 
Rashid [163]

Answer:

Because of its importance in summarizing your strategy, the Introduction and Overview of your business plan should be written last-B.

3 0
3 years ago
)In six months, your company plans to issue a 1.5 year zero coupon bond with a face value of $500,000 to finance a small acquisi
pishuonlain [190]

Answer:

$441,495

Explanation:

Since the information is incomplete, I looked for the missing part and found the attached information.

the current yield of a 1.5 years zero coupon bond = (100 / 89.9)¹/¹°⁵ - 1 = 0.0736 = 7.36%

the current yield of a 6 months zero coupon bond = (100 / 97.087)¹/⁰°⁵ - 1 = 0.0609 = 6.09%

now to calculate the future interest rate:

(1.0736²/1.0609) - 1 = 0.0865 = 8.65%

since we are told to determine the price of the bond:

(100/P)¹/¹°⁵ - 1 = 0.0865

(100/P)¹/¹°⁵ = 1.0865

100/P = 1.0865¹°⁵

100/P = 1.1325

100/1.1325 = P

P = 88.299

the expected price of the bond = 88.299% x $500,000 = $441,495

8 0
3 years ago
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