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3 years ago

I need help to get to 8.9 I need help to figure out the numbers for the empty boxes.

Mathematics

1 answer:

Rainbow [258]3 years ago

7 0

Answer:

Bottom row from left to right we have 0.4 0.3 0.3 0.1 0.5 0.5 Second row from right to left 0.7 0.6 0.4 0.6 1 On the Third row from right to left 1.3 1 1 1.6 On the Fourth row 2.3 2 2.6 On the Fith row 4.3 and 4.6 The last Row also the highest 8.9

Step-by-step explanation:

you take two numbers right and left add them and put the answer in the box above and in between

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Use a quadratic equation to find two real numbers with a sum of -43 and a product of 306.

vlabodo [156]

Answer:

Real numbers = 39 and 9

Step-by-step explanation:

The standard form of a quadratic equation is ax² + bx + c = 0

Given the following data;

a = 1

b = -43

c = 306

Quadratic equation formula is;

$x = \frac {-b \; \pm \sqrt {b^{2} - 4ac}}{2a}$

Substituting into the equation, we have;

$x = \frac {-(-43) \; \pm \sqrt {43^{2} - 4*1*306}}{2*1}$

$x = \frac {43 \pm \sqrt {1849 - 1224}}{2}$

$x = \frac {43 \pm \sqrt {625}}{2}$

$x = \frac {43 \pm 25}{2}$

$x_{1} = \frac {43 + 25}{2}$

$x_{1} = \frac {68}{2}$

$x_{1} = 39$

$x_{2} = \frac {43 - 25}{2}$

$x_{2} = \frac {18}{2}$

$x_{2} = 9$

Therefore, the two real numbers are 39 and 9.

The quadratic equation now becomes;

x² - 43x + 306 = (x - 39)(x - 9) = 0

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2 years ago

I need help. I don't know if I got this question right

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3 years ago

____________________

MaRussiya [10]

Step-by-step explanation:

the numbers of the yellow and white counters

= 288- 38 = 250.

the ratio of yellow to white = 1:4

so,

the numbers of the yellow counters =

1/(1+4) × 250 =1/5 ×250 = 50

the numbers of the white counters =

4/(1+4) ×250 = 4/5 ×250 = 200

and the numbers of the red counters = 38

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