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marshall27 [118]
4 years ago
10

When should a technician record a system's baseline data?

Computers and Technology
1 answer:
bija089 [108]4 years ago
3 0

Baseline data is a record of all the system performance specifications when the system is operating as designed. A technician should record a system's baseline data On a new system after it is installed.


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Write a function template that accepts an argument and returns its absolute value. The absolute value of a number is its value w
svetlana [45]

Answer:

The function in Java is as follows:

public static double func(double num){

       num = Math.abs(num);

       return num;

   }

Explanation:

This defines the function

public static double func(double num){

This determines the absolute function of num

       num = Math.abs(num);

This returns the calculated absolute value

       return num;

   }

8 0
3 years ago
We will pass in 2 values, X and Y. You should calculate XY XY and output only the final result. You will probably know that XY X
kiruha [24]

Answer:

import sys

# The value of the second argument is assigned to X

x = int(sys.argv[1])

# The value of the third argument is assigned to Y

y = int(sys.argv[2])

# The result of multiplication of x and y is assigned to 'result'

result = x * y

#The value of the result is displayed to the user

print("The result of multiplying ", x, "and ", y, "is", result)

Explanation:

First we import sys which allow us to read the argument passed when running the program. The argument is number starting from index 0; the name of the python file been executed is sys.argv[0] which is the first argument. The second argument is sys.argv[1] and the third argument is sys.argv[2].

The attached file is named multplyxy (it wasn't  saved as py file because the platform doesn't recognise py file); we can execute it by running: python3 multiplyxy.py 10 23

where x will be 10 and y will be 23.

To run the attached file; it content must be saved as a py file: multiplyxy.py

Download pdf
5 0
4 years ago
Brainly is brainly am I correct ​
Bezzdna [24]

Answer:

yes

Explanation:

its a app

hope it is correct

mark me as brainiest

7 0
3 years ago
Read 2 more answers
Compare and contrats the vain digestive system from the human digestive system.​
alina1380 [7]
No need to get political
4 0
3 years ago
The compare_strings function is supposed to compare just the alphanumeric content of two strings, ignoring upper vs lower case a
Korolek [52]

Answer:

There is a problem in the given code in the following statement:

Problem:

punctuation = r"[.?!,;:-']"

This produces the following error:

Error:

bad character range

Fix:

The hyphen - should be placed at the start or end of punctuation characters. Here the role of hyphen is to determine the range of characters. Another way is to escape the hyphen - using using backslash \ symbol.

So the above statement becomes:

punctuation = r"[-.?!,;:']"  

You can also do this:

punctuation = r"[.?!,;:'-]"  

You can also change this statement as:

punctuation = r"[.?!,;:\-']"

Explanation:

The complete program is as follows. I have added a print statement print('string1:',string1,'\nstring2:',string2) that prints the string1 and string2 followed by return string1 == string2  which either returns true or false. However you can omit this print('string1:',string1,'\nstring2:',string2) statement and the output will just display either true or false

import re  #to use regular expressions

def compare_strings(string1, string2):  #function compare_strings that takes two strings as argument and compares them

   string1 = string1.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   string2 = string2.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   punctuation = r"[-.?!,;:']"  #regular expression for punctuation characters

   string1 = re.sub(punctuation, r"", string1)  # specifies RE pattern i.e. punctuation in the 1st argument, new string r in 2nd argument, and a string to be handle i.e. string1 in the 3rd argument

   string2 = re.sub(punctuation, r"", string2)  # same as above statement but works on string2 as 3rd argument

   print('string1:',string1,'\nstring2:',string2)  #prints both the strings separated with a new line

   return string1 == string2  # compares strings and returns true if they matched else false

#function calls to test the working of the above function compare_strings

print(compare_strings("Have a Great Day!","Have a great day?")) # True

print(compare_strings("It's raining again.","its raining, again")) # True

print(compare_strings("Learn to count: 1, 2, 3.","Learn to count: one, two, three.")) # False

print(compare_strings("They found some body.","They found somebody.")) # False

The screenshot of the program along with its output is attached.

4 0
4 years ago
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