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Pavel [41]
2 years ago
15

Numerous engineering and scientific applications require finding solutions to a set of equations. Ex: 8x + 7y = 38 and 3x - 5y =

-1 have a solution x = 3, y = 2. Given integer coefficients of two linear equations with variables x and y, use brute force to find an integer solution for x and y in the range -10 to 10.
Ex: If the input is:

8
7
38
3
-5
-1
Then the output is:

x = 3 , y = 2
Use this brute force approach:

For every value of x from -10 to 10
For every value of y from -10 to 10
Check if the current x and y satisfy both equations. If so, output the solution, and finish.
Ex: If no solution is found, output:

There is no solution
Assume the two input equations have no more than one solution.

Note: Elegant mathematical techniques exist to solve such linear equations. However, for other kinds of equations or situations, brute force can be handy.
Computers and Technology
1 answer:
Gre4nikov [31]2 years ago
4 0

The brute strength method determines if each x and y value satisfies both conditions. To do this, we must iterate through each result in the specified range and insert them into both models.

<h3>What are Elegant mathematical technique?</h3>

ALGORITHM :

1. Take the values of all coefficients and SET flag = FALSE

2. Run a FOR loop for x in range (-10, 11). 11 won't be included.

2a. Inside the first FOR, start the y FOR loop in range(-10,11). 11 won't be included

2b. Inside the y FOR loop, check IF for a particular value of x and y both the equations satisfied.

2c. If yes, set flag TRUE and print values of x and y.

2d. ELSE the flag stays FALSE.

END FOR Y

END FOR X

3. Check if flag = FALSE, then print NO SOLUTION

PYTHON CODE :

a=int(input()) #taking input for each coefficient

b=int(input())

c= int(input())

a1= int(input())

b1= int(input())

c1= int(input())

flag = False

for x in range(-10,11): #checking for all values of x in range -10 to 10

for y in range(-10,11): #checking for all values of x in range -10 to 10

if (a  x + b  y – c == 0) and (a1*x + b1*y - c1 == 0) : #checking if the x and y values satisfy the equation

flag = True #setting the flag if solution is found

print('Solution : x = {-10, 10}, y = {-10, 10}'.format(x,y)) #if they satisfy print x & y

if flag = False : #if flag stays false, that means there is no solution

print('No solution')

OUTPUT : The output is given below.

More about the Elegant mathematical technique link is given below.

brainly.com/question/27934739

#SPJ1

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3 years ago
Modify the list according to the following: append the smallest value at the end of the list when all numbers in the list are ne
ddd [48]

Answer:

The solution code is written in Python 3:

  1. def modifyList(listNumber):
  2.    posCount = 0
  3.    negCount = 0
  4.    for x in listNumber:
  5.        if x > 0:
  6.            posCount += 1
  7.        else:
  8.            negCount += 1
  9.    
  10.    if(posCount == len(listNumber)):
  11.        listNumber.append(max(listNumber))
  12.    
  13.    if(negCount == len(listNumber)):
  14.        listNumber.append(min(listNumber))
  15.    
  16.    print(listNumber)
  17. modifyList([-1,-99,-81])
  18. modifyList([1,99,8])
  19. modifyList([-1,99,-81])

Explanation:

The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).

To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).

If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).

If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.

At last we can print the listNumber (Line 17).

If we test our function using the three sets of input list, we shall get the following results:

[-1, -99, -81, -99]

[1, 99, 8, 99]

[-1, 99, -81]

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3 years ago
________ is a record in a relational database.
leonid [27]

The answer that is a record in a relational database is called; A row

<h3>What is a record in relational database?</h3>

In relational databases, a record is defined as a group of related data held within the same structure. Furthermore, we can say that a record is a grouping of fields within a table that reference one particular object.

Now, in relational database, a row is called a record because each row, contains a unique instance of data or key for the categories defined by the columns.

Read more about Relational Database at; brainly.com/question/13262352

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4 0
2 years ago
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attashe74 [19]

Answer:

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Explanation:

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3 years ago
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Leviafan [203]

Answer:

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import math

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rate = 0.025

for i in range(1, 11):

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    print("Year "+str(i)+": "+str(round(amount,2)))

Explanation:

This line imports math library

import math

This line initializes principal amount to 8000

principal = 8000

This line initializes rate to 0.025

rate = 0.025

The following is an iteration from year 1 to 10

for i in range(1, 11):

    This calculates the amount at the end of the year

    amount = principal + principal * rate

    This calculates the amount at the beginning of the next year

    principal = amount

    This prints the calculated amount

    print("Year "+str(i)+": "+str(round(amount,2)))

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