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tamaranim1 [39]
3 years ago
5

Jax eats 6 ounces of formula at dinner and 6.5 ounces of formula before bed. How much does he eat for both meals?

Mathematics
1 answer:
Anton [14]3 years ago
6 0

Answer:

12.5 oz

Step-by-step explanation:

i am pretty sure you just have to add them together

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Suppose that many large samples are taken from a population and that the
rewona [7]

Answer:

0.22 -1 *0.029 =0.191

0.22 +1 *0.029 =0.249

And the best option would be:

D. (0.191 to 0.249)

Step-by-step explanation:

For this case we know that the mean is:

\bar X = 0.22

And the standard error is given by:

SE = 0.029

We want to construct a 68% confidence interval so then the significance level would be :

\alpha=1-0.68 = 0.32 and \alpha/2 =0.16. The confidence interval is given by:

\bar X \pm z_{\alpha/2} SE

Now we can find the critical value using the normal standard distribution and we got looking for a quantile who accumulate 0.16 of the area on each tail and we got:

z_{\alpha/2}= 1

And replacing we got:

0.22 -1 *0.029 =0.191

0.22 +1 *0.029 =0.249

And the best option would be:

D. (0.191 to 0.249)

5 0
3 years ago
the line containing the altitude to the hypotenuse of a right triangle whose vertices are p(-1, 1), q(3, 5), and r(5, -5).
finlep [7]

The equation of the straight line is given by 5y-x=6

An equation can be used to describe a straight line drawn on the Cartesian Plane. These equations have a generic structure and can change based on the slope and where the line intersects the axes.

We will greatly simplify this issue by utilizing the fact that this triangle is specified as a right triangle. We would have had to establish the presence of a right angle if it had been presented as a general triangle.

The segment QR is the hypotenuse of the triangle.

Any side's altitude is located along a line that is perpendicular to that side. We are aware that the slopes of perpendicular lines are negative reciprocals, or:

Slope of line joining  Q(3, 5) and R(5, -5)

m=\frac{y_2-y_1}{x_2-x_1}

Hence slope is= -10/2= -5

Now we know that for two perpendicular line the slope of one line is the negative reciprocal of the other.

Slope of line perpendicular to QR=1/5

This line passes through P(-1,1)

Equation of the straight line that passes through (1,-1) and with a slope of 1/5 is given by:

(y-y_1)=m(x-x_1)\\

Substituting the values we get:

y-1=1/5(x+1)

or,5y-5=x+1

or,5y-x=6

Hence the equation of the required line is : 5y-x=6

To learn more about straight lines visit:

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8 0
2 years ago
Which expression is equivalent to (x Superscript one-half Baseline y Superscript negative one-fourth Baseline z) Superscript neg
Darina [25.2K]

By using exponent properties, we will get the simplified expression:

x^{-1}*y^{1/2}*z^2

<h3>How to simplify the given expression?</h3>

Here we have the expression:

(x^{1/2}*y^{-1/4}*z)^{-2}

Remember the exponent properties:

(a^n)^m = a^{n*m}

And:

(a*b)^n = (a^n)*(b^n)

So using these two properties, we can rewrite:

(x^{1/2})^{-2}*(y^{-1/4})^{-2}*(z)^{-2}\\\\(x^{-2*1/2})*(y^{-2*-1/4})*(z^{-2}})\\\\x^{-1}*y^{1/2}*z^2

So we conclude that the completely simplified expression is:

x^{-1}*y^{1/2}*z^2

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8 0
2 years ago
Tyger is trying to eat less sugar in his diet.He reduces his sugar intake from 15 spoons a day to 9 1/2 spoons a day. What is th
seraphim [82]

Answer:the percentage decrease is 36.67%

Step-by-step explanation:

Initial amount of sugar in his diet is 15 spoons in a day. Currently, the amount of sugar in his diet is 9 1/2 spoons in a day. Converting to decimal, it becomes 9.5 spoon in a day. The amount by which he reduced his sugar intake is 15 - 9.5 = 5.5 spoons.

Percentage decrease would be expressed as

Amount by which the intake decreased/ initial intake × 100

It becomes

5.5/15 × 100 = 36.67%

8 0
3 years ago
In the xy-coordinate plane shown, line L passes through point C and has a slope of -2. A dilation of line {with center A and a s
masya89 [10]

Answer:

C' (-4 , 2)

slope of new line = line "L" = -2

Step-by-step explanation:

C (x₀,y₀): (0,2)    dilation center (h,k): (2,2)     scale factor (sf): 3

C' (x,y)

x = 2 + 3*(0-2) = -4            x = h + sf*(x₀ - h)

y = 2 + 3*(2-2) = 2             y = k + sf*(y₀ - k)

C' (-4 , 2)

slope of new line = line "L" = -2

8 0
2 years ago
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