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3 years ago

14.53 less then or greater then 16.3

Mathematics

2 answers:

Natalka [10]3 years ago

5 0

Answer:

14.53 is less than 16.3

yes this is mathematics

stich3 [128]3 years ago

3 0

Answer:

14.53 is less than 16.3, that is the answer

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Jeff is buying books at a used bookstore he wants to approximate the total cost of his purchase before checking out which amount

amid [387]

Answer:

$35.00

Step-by-step explanation:

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2 years ago

What is the value of 7m - 3n when m = 3 and n = 2? A. 5 B. 15 C. 24 D. 36

Bezzdna [24]

Well just plug those two numbers into the equation: 7(3) - 3(2) Which equals 15 so B) 15

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3 years ago

Read 2 more answers

Come graphs find the value of h,k, or a

TEA [102]

Answers:

Translation 3 units up
k = 3

============================================================

Explanation:

The y intercept of the black f(x) curve is at (0,1)

The y intercept of the blue curve is at (0,4)

To go from y = 1 to y = 4, we add 3

So we shift 3 units up to go from the f(x) curve to the g(x) curve.

The value of k is 3, which corresponds exactly to the vertical shift. If we shifted down, then k would be negative.

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3 years ago

Five years ago ,a father was four times as old as his son.In five years time the father will be twice as old as the son.If x and

andrew-mc [135]

B 4y-y=15;x-2y=5 is the correct one

5 0

3 years ago

8) through: (-3, -2), perp. to y = x – 1 A) y=-5x – 1 B) y=-4x – 5 C) y=-x – 5 D) y=-5x – 4

nexus9112 [7]

Answer:

The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

Solution:

Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)

We have to find the line equation which is perpendicular to above given line and passing through the given point.

Now, let us find the slope of the given line equation.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-1}=1$

We know that, product of slopes of perpendicular lines is -1.

So, 1 $\times$ slope of perpendicular line = -1

slope of perpendicular line = -1

Now let us write point slope form for our required line.

$\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)$

y – (-2) = -1(x – (-3))

y + 2 = -1(x + 3)

y + 2 = -x – 3

x + y + 2 + 3 = 0

x + y + 5 = 0

y = -x -5

Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

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3 years ago