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3 years ago

Consider these dimensions for a cylindrical aquarium.

Mathematics

2 answers:

LUCKY_DIMON [66]3 years ago

8 0

Answer:

27,489 ft^3

Step-by-step explanation:

The aquarium is cylindrical in shape. To determine the amount of water that will fill the tank, we would apply the formula for determining the volume of a cylinder.

The Volume of a cylinder can be written as:

Volume V = πr^2 h ....1

Given;

Radius r = 25 ft

height h = 14 ft

Substituting the given values into the equation 1;

V = π×25^2 × 14

V = 27488.94 ft^3

V = 27,489 ft^3

-BARSIC- [3]3 years ago

7 0

Answer: 27475 cubic feet of water will fill the tank.

Step-by-step explanation:

The aquarium is cylindrical in shape. To determine the amount of water that will fill the tank, we would apply the formula for determining the volume of a cylinder. It is expressed as

Volume = πr²h

Where

r represents the radius of the aquarium.

h represents the radius of the aquarium.

π is a constant whose value is 3.14

From the information given,

h = 14 ft

r = 25 ft

Therefore,

Volume = 3.14 × 25² × 14 = 27475 cubic feet

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What are the coordinates of the endpoints of the midsegment for △XYZ that is parallel to XZ⎯⎯⎯⎯⎯ ?

Ksenya-84 [330]

The coordinates of the endpoints of the mid-segment of Δ XYZ that parallel to XZ are (1 , 6) and (1 , 3)

Step-by-step explanation:

In a triangle the segment which joining the mid points of two sides:

Parallel to the 3rd side
Its length is equal half the length of the 3rd side
It's called the mid-segment of the triangle

In Δ XYZ

∵ Vertex X is (0 , 7)

∵ Vertex Y is (2 , 5)

∵ Vertex Z is (0 , 1)

∵ The mid-segment of Δ XYZ is parallel to XZ

- The mid-segment intersects the other two sides of the Δ

at their mid-points

∴ The mid-segment intersects XY and YZ at their midpoints

∴ The endpoints of the mid-segment are the midpoints of

XY and YZ

The mid point of a segments whose endpoints are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

∵ X = (0 , 7) and Y = (2 , 5)

∴ $x_{1}$ = 0 and $x_{2}$ = 2

∴ $y_{1}$ = 7 and $y_{2}$ = 5

∵ The mid point of XY = $(\frac{0+2}{2},\frac{7+5}{2})$

∴ The mid point of XY = $(\frac{2}{2},\frac{12}{2})$

∴ The mid point of XY = (1 , 6)

∵ Z = (0 , 1) and Y = (2 , 5)

∴ $x_{1}$ = 0 and $x_{2}$ = 2

∴ $y_{1}$ = 1 and $y_{2}$ = 5

∵ The mid point of ZY = $(\frac{0+2}{2},\frac{1+5}{2})$

∴ The mid point of ZY = $(\frac{2}{2},\frac{6}{2})$

∴ The mid point of ZY = (1 , 3)

∵ The endpoints of the mid-segment are the midpoints of

XY and YZ

∴ The end points of the mid segments are (1 , 6) and (1 , 3)

The coordinates of the endpoints of the mid-segment of Δ XYZ that parallel to XZ are (1 , 6) and (1 , 3)

Learn more:

You can learn more about the mid-point in brainly.com/question/5223123

#LearnwithBrainly

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2 years ago

Could someone please list all of the basic derivative rules?

olchik [2.2K]

Answer:

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3 years ago

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DochEvi [55]

Answer:

(-3/2x+1) + (3/x-1)

Step-by-step explanation:

Dont put the answer in parenthesis, I just did that to seprate it so it was easier to read. If you need it to be put in word form for it to be easier for you to understand, its "negative three divided by two x plus one, plus 3 divided by x minus 1"

First, rewrite the expression as 3x+6/2x^2+x-2x-1

Then, factor the expression, 3x+6/x*(2x+1)-(2x+1) (*=multiply)

Then, write a new fraction for each factor in the denominator, then write a new fraction, 3x+6/(2x+1)*(x-1) to (A)/2x+1 + B/x-1)

Then write terms in the numerators, for now we will use A and B.

Now we set the sum of the fractions equal to the original fraction.

3x+6/(2x+1)*(x-1) = A)/2x+1 + B/x-1).

Then reorder and group the terms, giving you 3x+6=(A+2B)x+(-A+B).

Now equate the coefficiants, {6= -A+B, 3= A+2B

Then substitute back, (A, B)=(-3, 3)

Now finally, just rewrite the fraction. (-3/2x+1) + (3/x-1)

Hope this helps! Sorry its kind of long.

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