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3 years ago

Consider these dimensions for a cylindrical aquarium.

Mathematics

2 answers:

LUCKY_DIMON [66]3 years ago

8 0

Answer:

27,489 ft^3

Step-by-step explanation:

The aquarium is cylindrical in shape. To determine the amount of water that will fill the tank, we would apply the formula for determining the volume of a cylinder.

The Volume of a cylinder can be written as:

Volume V = πr^2 h ....1

Given;

Radius r = 25 ft

height h = 14 ft

Substituting the given values into the equation 1;

V = π×25^2 × 14

V = 27488.94 ft^3

V = 27,489 ft^3

-BARSIC- [3]3 years ago

7 0

Answer: 27475 cubic feet of water will fill the tank.

Step-by-step explanation:

The aquarium is cylindrical in shape. To determine the amount of water that will fill the tank, we would apply the formula for determining the volume of a cylinder. It is expressed as

Volume = πr²h

Where

r represents the radius of the aquarium.

h represents the radius of the aquarium.

π is a constant whose value is 3.14

From the information given,

h = 14 ft

r = 25 ft

Therefore,

Volume = 3.14 × 25² × 14 = 27475 cubic feet

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$log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x$

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Thus we get,

$log_b162 = x + 4y$

$b) log_b 324$

Break 324 down to primes:

$324 = 2^2 \times 3^4$

$log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y$

$c) log_b\frac{8}{9}$

By rule 2

$log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} = 3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} = 3x - 2y$

$d) \frac{log_b27}{log_b16}$

By rule 2

$\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} = 3y - 4x$

Thus the given are evaluated in terms of x and y

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