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svp [43]
3 years ago
9

PLEASE HELP ME!!!!

Mathematics
1 answer:
Damm [24]3 years ago
7 0

Answer:

  • sin C=h/a
  • substitution property of equality
  • commutative property of multiplication

Step-by-step explanation:

Because two points determine a line, you can draw altitude​ BD perpendicular to AC with height h. By the definition of a sine ratio, <u>sin(C) = h/a</u>, which can be rearranged into​ a·sin(C) = h​. The area of △ABC is A=1/2bh. The <u>substitution property of equality</u> can be used to write A=1/2b(a sinC), which becomes A=1/2ab(sinC) by the <u>commutative property of multiplication</u>.

___

The mnemonic SOH CAH TOA reminds you that the sine ratio is ...

  Sin = Opposite/Hypotenuse

Here, the side of the right triangle opposite angle C is designated "h", the height of ∆ABC. The hypotenuse of that right triangle is side "a". So ...

  sin(C) = h/a

__

The substitution property of equality lets you replace any expression with its equal. Here, we have h=a·sin(C), so we can use a·sin(C) in place of h in the formula for triangle area:

  1/2bh = 1/2ba·sin(C)

__

The commutative property of multiplication lets you rearrange the order of the factors in a product, so ...

  ba = ab

and

  A = 1/2ba·sin(C) = 1/2ab·sin(C)

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When you write a number that is less than 1 in scientific notation how does the power of 10 differ from when you write a number
Irina18 [472]

When you write a number that is less than 1 in scientific notation how does the power of 10 differ from when you write a number greater than 1 in scientific notation?​

Answer : In scientific notation all numbers are written in the form m × 10ⁿ. If the number is less than 1, ten is raised to a negative power, so : m × 10⁻ⁿ.​

Example : a decimal number less than 1 is 0.02 = 2 x 10⁻² in scientific notation.

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3 0
4 years ago
(ü) Write 2067 correct to the nearest hundred.​
zepelin [54]

I think 2100

I'm not sure dont blame if it's wrong

4 0
3 years ago
Allison is buying movie tickets for she and her friends. The price of each ticket is $8.50 and she spent a total of $42.50. Writ
pochemuha
P = price of tickets
8.50p = 42.50

you then divide 8.50 on both sides
8.50p = 42.50
——— ———
8.50 8.50
p = 5

meaning Allison bought 5 tickets in total.
7 0
3 years ago
Leslie mows lawns to earn money. For each customer, she charges $2.00 for gas and $3.00 per 12 hour of work. Let x represent the
RUDIKE [14]

Answer:

See Explanation

Step-by-step explanation:

Given

Gas = \$2.00

Rate = \$3.00/12hr

\begin{array}{ccc}{Row} & {Hours} & {Earnings} & {A} & {2} & { } & {B} & {4} & { } & {C} & {6} &{ } \ \end{array} ---- Missing table

Required

Complete the table and plot the graph

First, we determine the equation of the table:

Gas = \$2.00

Rate = \$3.00/12hr implies that:

Rate = \$0.25/hr

So:

y = Gas + Rate * x

y = 2+ 0.25* x

y = 2+ 0.25 x

To complete the table, we have:

x = 2

y = 2+ 0.25 x = 2+0.25 * 2 = 2.5

x = 4

y = 2+ 0.25 x = 2+0.25 * 4 = 3

x = 6

y = 2+ 0.25 x = 2+0.25 * 6 = 3.5

So, the complete table is:

\begin{array}{ccc}{Row} & {Hours} & {Earnings} & {A} & {2} & {2.5} & {B} & {4} & {3} & {C} & {6} &{3.5} \ \end{array}

See attachment for graph

6 0
3 years ago
Susan Bought a soccer ball for her brother. She wants to fool him by putting the ball into a box before wrapping it. The balls c
frutty [35]

Answer:

Ball cannot be fit inside the box.

Step-by-step explanation:

Given:

Circumference of ball = 26 inches

Dimension of box = 8.25 in x 8.25 in x 8.5 in.

We need to find the whether ball gets fits inside the box.

First we will find the Diameter of ball.

Circumference of ball is given so we will find radius of the ball.

Circumference of the sphere is equal to 2 times π times radius.

framing in equation form we get;

2\pi \times r =26\\\\r= \frac{26}{2\pi}= 4.14\ in.

Now we will find the Diameter of the ball.

Diameter of ball is equal to 2 times radius.

framing in equation form we get;

Diameter of ball =  2\times 4.14 = 8.28\ in

Now given that two parallel sides of box has dimension which is 8.25 in.

Since Dimension of box is smaller than diameter of the ball.

Hence we can say that ball cannot be fit inside the box.

5 0
3 years ago
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