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Nimfa-mama [501]
3 years ago
14

HELP Write an equation of a line passing through (-8, 6) and parallel to the line y=-4x - 1

Mathematics
1 answer:
MArishka [77]3 years ago
4 0

The line is parallel so it has the same slope as the other line, -4.

Substitute the x and y variables with the given points and find the y-intercept.

(-8, 6)

y = -4x + b

6 = -4(8) + b

6 = -32 + b

6 + 32 = b

38 = b

So the equation is:

y = -4 + 38

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5 - 3tan3x = 0 trên -π< x < π.
serious [3.7K]

Answer:

x = 0.343

Step-by-step explanation:

We want to solve:

5 - 3tan(3x) = 0

such that:

-π< x < π

where π = 3.14

then:

-3.14 < x < 3.14

Let's solve the equation:

5 - 3tan(3x) = 0

-3tan(3x) = -5

tan(3x) = -5/-3 = 5/3

Now we can use the inverse tan function, Atan(x).

Remember that:

Atan( tan(x) ) = tan( Atan(x)) = x

Then if we apply that function to both sides, we get:

Atan( tan(3x)) = Atan(5/3)

3x = Atan(5/3)

x = Atan(5/3)/3 = 0.343

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3 years ago
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julia-pushkina [17]

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Step-by-step explanation:

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ALGEBRA 1, SEM. 2
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2•(1/4)^(2-1)= 2•(1/4)= 1/2
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