Answer:
<h3>
f(x) = - ⁴/₉(x - 3)² + 6</h3>
Step-by-step explanation:
The vertex form of the equation of the parabola with vertex (h, k) is:
f(x) = a(x - h)² + k
So for vertex (3, 6) it will be:
f(x) = a(x - 3)² + 6
<u>y intercept: 2</u> means f(0) = 2
f(0) = a(0 - 3)² + 6
2 = a(-3)² + 6
2 -6 = 9a + 6 -6
-4 = 9a
a = ⁻⁴/₉
Therefore:
The vertex form of quardatic function with vertex: (3,6) and y intercept: 2 is
<u>f(x) = - ⁴/₉(x - 3)² + 6</u>
Find the slope:
y₂ - y₁ / x₂ - x₁
-1 - 2 / 0 - 4
-3 / -4
3/4
y = mx + b
y = 3/4x + b
Substitute any of the point's coordinate in the equation.
I'll pick (0,-1)
y = 3/4x + b
-1 = 3/4(0) + b
-1 = 0 + b
-1 = b
y-intercept = -1
y-intercept Equation:
y = 3/4x - 1
Point-slope form:
y - 2 = 3/4(x - 4)
Standard form:
-3/4x + y = -1
Answer:
Is this like a random question or did you forget to put something? But if it is then B ig
Step-by-step explanation:
<span>f(-3) for f(x)=3x-x^2
</span>f(-3)=3(-3) -(-3)^2
f(-3)=-9 - 9
f(-3)=-18
answer is the last one on the picture
Answer:
pay attention in class
Step-by-step explanation:
936
-3
-------
=312
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so its 3.12
