The question is this one:

Which of the following describes a major role of gravity in star formation?

MrRissso [65]

The ans is B) because gravity attracts and doesn't repel

7 0

4 years ago

A sinusoidal wave of wavelength 2.00m and amplitude 0.100 m travels on a string with a speed of 1.00 m/s to the right. At t = 0

Shkiper50 [21]

The frequency and angular frequency are 0.500 Hertz and 3.142 rad/s. respectively.
The angular wave number is equal to 3.142 rad/m.
The wave function for this wave is given by: y = Asin(kx - ωt + Φ).
The equation of motion for the left end of the string is given by: y = 0.100sin(3.142x - 3.142t + 0).
The equation of motion for the left end of the string at x = 1.50 m to the right is equal to y = 0.100sin(4.71 - 3.142t + 0).The maximum speed of any point on the string is 0.3142 m/s.

<h3>How to calculate the frequency and angular frequency?</h3>

First of all, we would determine the frequency of this wave by using this formula:

Frequency = wavelength/speed

Frequency = 0.100/2.00

Frequency = 0.500 Hertz.

For the angular frequency, we have:

Angular frequency, ω = 2πf

Angular frequency, ω = 2 × 3.142 × 0.500

Angular frequency, ω = 3.142 rad/s.

<h3>How to determine the angular wave number?</h3>

Angular wave number, k = 2π/∧

Angular wave number, k = (2 × 3.142)/2.00

Angular wave number, k = 3.142 rad/m.

<h3>How to determine the wave function for this wave?</h3>

Mathematically, the wave function for this wave is given by:

y = Asin(kx - ωt + Φ)

For the equation of motion for the left end of the string, we have:

y = 0.100sin(3.142x - 3.142t + 0)

For the equation of motion for the left end of the string at x = 1.50 m to the right, we have:

y = 0.100sin(3.142x - 3.142t + 0)

y = 0.100sin(3.142(1.5) - 3.142t + 0)

y = 0.100sin(4.71 - 3.142t + 0)

<h3>What is the maximum speed of any point on the string?</h3>

Vy = 0.100sin(- 3.142)cos(3.142x - 3.142t)

Vy ≤ 0.3142 m/s (since cosine varies +1 and -1).

Read more on wave function here: brainly.com/question/11181093

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Complete Question:

A sinusoidal wave of wavelength 2.00 m and amplitude 0.100 m travels on a string with a speed of 1.00 m/s to the right. Initially, the left end of the string is at the origin. Find:

(a) the frequency and angular frequency,

(b) the angular wave number, and

(c) the wave function for this wave.

Determine the equation of motion in SI units for

(d) the left end of the string, and

(e) the point on the string at x = 1.50 m to the right of the left end.

(f) What is the maximum speed of any point on the string?

5 0

2 years ago

A projectile is fired with an initial speed of 100 m/s and angle of elevation 30 degrees. The projectile eventually hits the gro

zaharov [31]

Answer:

Explanation:

Given

launch velocity $u=100\ m/s$

Launch angle $\theta =30^{\circ}$

Range of Projectile $R=\frac{u^2\sin 2\theta }{g}$

$R=\frac{100^2\times \sin (2\times30)}{9.8}$

$R=883.699\approx 883.7$

Horizontal velocity remain same and only vertical velocity changes.

Initially vertical velocity is in upward direction but as soon as it reaches the ground its direction change but magnitude remain same.

$u_y=100\sin (30)=50\ m/s$

$u_x=100\cos (30)=86.60\ m/s$

$u_{net}=\sqrt{(50)^2+(86.60)^2}$

$u_{net}=99.99\approx 100\ m/s$

7 0

3 years ago

A 2.00-kg block is pushed against a spring with negligible mass and force constant k = 400 N/m, compressing it 0.220 m. When the

marin [14]

Answer:

0.82052 m

Explanation:

potential energy of spring = kinetic energy

=> 0.5kx^2 = 0.5mv^2

=> $v=\sqrt{\frac{kx^2}{m} }$

$v=\sqrt{\frac{400\times 0.220^2}{2} }$

v= 3.11127 m/s

angle = 37°

thus height = distance×sin(37) = D×0.60182

Also,

m×g×h = 0.5×m×v^2

=> 2×9.8×D×0.60182 = 0.5×2×3.11127×3.11127

=> D = 0.82052 m

4 0

3 years ago

Acceleration is defined as the change in velocity divided by

denpristay [2]

Answer:

Time elapsed

Explanation:

Acceleration is a vector quantity. It is defined as:

$a=\frac{v-u}{t}$

where

v is the final velocity

u is the initial velocity

t is the time elapsed

Acceleration is measured in meters per second squared (m/s^2). It must be noticed that acceleration is a vector, so it also has a direction. In particular:

- when acceleration is negative, it means that the object is slowing down, so acceleration is in opposite direction to the velocity

- when acceleration is positive, it means that the object is speeding up, so acceleration is in the same direction as the velocity

3 0

3 years ago