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4 years ago

Which of the following describes a major role of gravity in star formation?

Physics

2 answers:

artcher [175]4 years ago

8 0

Answer:

B. Gravity compresses gases at the center of a solar nebula until temperatures are high enough for nuclear fusion to occur.

Explanation:

Stars are born in stellar nurseries known as nebula. Sun, the star at the center of the solar system was born in the solar nebula.

Nebula is a molecular cloud of dust and gases. Due to gravity, this cloud collapses under its own weight and condenses to form the core. It gathers more mass till the temperature of the core rises enough to start the nuclear fusion reaction. A star is born then.

MrRissso [65]4 years ago

7 0

The ans is B) because gravity attracts and doesn't repel

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lora16 [44]

Answer:

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Explanation:

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3 years ago

A sports car accelerates at a constant rate from rest to a speed of 90 km/hr in 8 s. What is its acceleration?

AfilCa [17]

First convert 90km/hr to m/s.

Initiate velocity = 0m/s (car was at rest)

Final velocity is 25m/s (90km/hr converted)

25m/s - 0m/s / 8s = 3.125 m/s^s

Therefore the answer is option A (3.13m/s^2)

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3 years ago

A 40 foot beam that weighs 125 pounds is supported at the two ends by walls. It also supports a 600 pound AC unit 5 feet from th

Dmitrij [34]

Answer:

A) 588 pounds

Explanation:

According to the given conditions, we assume the beam to be simply supported at the ends carrying a uniformly distributed load of 125 pounds per feet and a point load of 600 pounds acting at 5 feet from the right support.

Referring the schematic:

<u>Moment about any point will be zero in equilibrium condition. </u>

∴Take moment about point L

$F_r\times 40=125\times 20+35\times 600$

$F_r=587.5 lb$

8 0

4 years ago

A particular coaxial cable is comprised of inner and outer conductors having radii 1 mm and 3 mm respectively, separated by air.

noname [10]

Answer:

The value is $\rho_s = 4.026 *10^{-6} \ C/m^2$

Explanation:

From the question we are told that

The radius of the inner conductor is $r_1 = 1 \ mm = 0.001 \ m$

The radius of the outer conductor is $r_2 = 3 \ mm = 0.003 \ m$

The potential at the outer conductor is $V = 1.5 kV = 1.5 *10^{3} \ V$

Generally the capacitance per length of the capacitor like set up of the two conductors is

$C= \frac{2 * \pi * \epsilon_o }{ ln [\frac{r_2}{r_1} ]}$

Here $\epsilon_o$ is the permitivity of free space with value $\epsilon_o = 8.85*10^{-12} C/(V \cdot m)$

=> $C= \frac{2 * 3.142 * 8.85*10^{-12} }{ ln [\frac{0.003}{0.001} ]}$

=> $C= 50.6 *10^{-12} \ F/m$

Generally given that the potential of the outer conductor with respect to the inner conductor is positive it then mean that the outer conductor is positively charge

Generally the line charge density of the outer conductor is mathematically represented as

$\rho_l = C * V$