Answer:
The amount of potential energy that was initially stored in the spring is 88.8 J.
Explanation:
Given that,
Mass of block = 1.60 kg
Angle = 30.0°
Distance = 6.55 m
Speed = 7.50 m/s
Coefficient of kinetic friction = 0.50
We need to calculate the amount of potential energy
Using formula of conservation of energy between point A and B
![U_{A}+k_{A}+w_{A}=U_{B}+k_{B}](https://tex.z-dn.net/?f=U_%7BA%7D%2Bk_%7BA%7D%2Bw_%7BA%7D%3DU_%7BB%7D%2Bk_%7BB%7D)
![U_{A}+0-fd=mgy+\dfrac{1}{2}mv^2](https://tex.z-dn.net/?f=U_%7BA%7D%2B0-fd%3Dmgy%2B%5Cdfrac%7B1%7D%7B2%7Dmv%5E2)
![U_{A}=\mu mg\cos\theta\times d+mg h\sin\theta+\dfrac{1}{2}mv^2](https://tex.z-dn.net/?f=U_%7BA%7D%3D%5Cmu%20mg%5Ccos%5Ctheta%5Ctimes%20d%2Bmg%20h%5Csin%5Ctheta%2B%5Cdfrac%7B1%7D%7B2%7Dmv%5E2)
Put the value into the formula
![U_{A}=0.50\times1.60\times9.8\cos30\times6.55+1.60\times9.8\times6.55\sin30+\dfrac{1}{2}\times1.60\times(7.50)^2](https://tex.z-dn.net/?f=U_%7BA%7D%3D0.50%5Ctimes1.60%5Ctimes9.8%5Ccos30%5Ctimes6.55%2B1.60%5Ctimes9.8%5Ctimes6.55%5Csin30%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes1.60%5Ctimes%287.50%29%5E2)
![U_{A}=88.8\ J](https://tex.z-dn.net/?f=U_%7BA%7D%3D88.8%5C%20J)
Hence, The amount of potential energy that was initially stored in the spring is 88.8 J.
Answer:
laws of motion relate an object’s motion to the forces acting on it. In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
It would result in stiffness and pain. Additional stress would be put onto the joints as well. Hope this helps, cheers!