A survey was held to find the time taken by students to reach school from their homes. Each student was asked to choose from 10,
1 answer:
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Answer:
D)
90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month
(0.52846 , 0.75166)
Step-by-step explanation:
<u><em>Step:-1</em></u>
Given that the random sample size 'n' = 50
The sample proportion
90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month
<u><em>Step(ii):-</em></u>
Level of significance = 0.90
Z₀.₉₀ = 1.645
(0.64 -1.645(0.06788) , (0.64 + 1.645(0.06788)
(0.52846 , 0.75166)
<u><em>Final answer:-</em></u>
90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month
(0.52846 , 0.75166)