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harkovskaia [24]
3 years ago
13

Stacy owes $40 on her credit card. After she made a payment, her new balance was $10. What was the amount of her

Mathematics
2 answers:
Yakvenalex [24]3 years ago
6 0

Answer:

Step-by-step explanation:

x  + 40 = 10

x = -30

She paid $30 on her credit card

Licemer1 [7]3 years ago
5 0
I agree with the other person $30
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2^4. 2^5-(2^2)^2 <br> Simplify the expression
11Alexandr11 [23.1K]

Answer:

Today: Monday, 12 October 2020

Hour: 17.31 WIB (in Indonesian)

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

2⁴ × 2⁵ - (2²)²

= 2⁹ - 2⁴

= 512 - 16

= 496

7 0
3 years ago
Please Hurry, I need an answer, quick my assignment is due today.
lys-0071 [83]

Answer:

8.25 hrs

Step-by-step explanation:

it takes 3/4 to replace all tires in a car

you then multiply 3/4 by 11

5 0
3 years ago
1.1 solve for x, where 0°&lt; x 90°. write your answer to one decimal place. 1.1.1 tanx=sin38° 1.1.2cosec( x+10°)=1.345​
snow_lady [41]

The value of x in tan(x)=sin38° is 31.6 and the value of x in cosec(x+10°)=1.345​ is 38.0

<h3>How to solve the trigonometry ratios?</h3>

The equations are given as:

tan(x)=sin38°

cosec( x+10°)=1.345​

In tan(x)=sin38°, we have:

tan(x)=0.6157

Take the arc tan of both sides

x = 31.6

Also, we have:

cosec(x+10°)=1.345​

Take the inverse of both sides

sin(x+10°) = 0.7434

Take the arc sin of both sides

x+10 = 48.0

Subtract 10 from both sides

x = 38.0

Hence, the value of x in tan(x)=sin38° is 31.6 and the value of x in cosec(x+10°)=1.345​ is 38.0

Read more about trigonometry ratios at:

brainly.com/question/11967894

#SPJ1

5 0
2 years ago
The average weight of the class of 35 students was 45 KG. with the admission of a new student the average weight came down to 44
melamori03 [73]

The weight of the new student is 27 kg.

Average weight

= total weight ÷total number of students

<h3>1) Define variables</h3>

Let the total weight of the 35 students be y kg and the weight of the new student be x kg.

<h3>2) Find the total weight of the 35 students</h3>

<u>45 =  \frac{y}{35}</u>

y= 35(45)

y= 1575 kg

<h3>3) Write an expression for average weight of students after the addition of the new student</h3>

New total number of students

= 35 +1

= 36

Total weight

= total weight of 35 students +weight of new students

= y +x

44.5  =  \frac{y + x}{36}

<h3>4) Substitute the value of y</h3>

44.5 =  \frac{1575 + x}{36}

<h3>5) Solve for x</h3>

36(44.5)= 1575 +x

1602= x +1575

<em>Subtract 1575 from both sides:</em>

x= 1602 -1575

x= 27

Thus, the weight of the new student is 27 kg.

7 0
3 years ago
jamie has 8/10 of a candy bar leftover. He wants to spilt it into 1/3 pieces . How many 1/3 pieces can he make
Len [333]
I think it might be 2.4 or 2
8 0
3 years ago
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