Answer:
C. 1/8
Step-by-step explanation:
You gotta find the LCD and combine
R would equal -189, there is step by step in the picture
3/4 on the minute hand of a clock would be 45.
example: 6:45
Answer:
Step-by-step explanation:
Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.
Problem 1:
(x²)/4 +y²= 1
y= x+1
*substitute for y*
Now we have a one-variable equation we can solve-
x²/4 + (x+1)² = 1
x²/4 + (x+1)(x+1)= 1
x²/4 + x²+2x+1= 1
*subtract 1 from both sides to set equal to 0*
x²/4 +x^2+2x=0
x²/4 can also be 1/4 * x²
1/4 * x² +1*x² +2x = 0
*combine like terms*
5/4 * x^2+2x+ 0 =0
now, you can use the quadratic equation to solve for x
a= 5/4
b= 2
c=0
the syntax on this will be rough, but I'll do my best...
x= (-b ± √(b²-4ac))/(2a)
x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))
x= (-2 ±√(4-0))/(2.5)
x= (-2±2)/2.5
x will have 2 answers because of ±
x= 0 or x= 1.6
now plug that back into one of the equations and solve.
y= 0+1 = 1
y= 1.6+1= 2.6
Hopefully this explanation was enough to help you solve problem 2.
Problem 2:
x² + y² -16y +39= 0
y²- x² -9= 0
The closest to the maximum number of cups the punch bowl can hold is 30
<h3>How to determine the number of cups?</h3>
The given parameters are:
1 cup = 15 cubic inches
Diameter of bowl, d = 12 inches
The radius is the half of the diameter.
So, we have:
r = 6
The volume of the bowl is then calculated using:

This gives

Evaluate
V = 452.16
The maximum number of cups is then calculated using:
Cups = 452.16/15
Evaluate
Cups = 30.1444
Approximate
Cups = 30
Hence, the closest to the maximum number of cups the punch bowl can hold is 30
Read more about volumes at:
brainly.com/question/1972490
#SPJ1