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2 years ago

When constructing an angle bisector of an angle, the first step is to draw

Mathematics

2 answers:

Mekhanik [1.2K]2 years ago

6 0

I think it’s a srry if it’s wrong

egoroff_w [7]2 years ago

6 0

I am pretty sure it’s A

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what are the steps to answer this question? Jeff is baking a cake. The recipe says that he has to mix 32 grams of powder to the

Deffense [45]

Well what I would do first is to divide 128 by 32 which I do believe gets you 4. So now you know that 1 cup of powder can make 4 servings. So you now know that each serving only requires 1/4 cup of the powder.

So now we know Jeff went over so now we have Jeff added 2/3 and he only needs 1/4. I would now make them both equivalent by multiplying the numerator and denominator of 2/3 by 4 and the same for 1/4 but instead by 4 multiply it by 3 which you would get 2/3=8/12 and 1/4=3/12. Now subtract the two to get your answer.

8/12-3/12=5/12

Answer: He went over and he needs to remove 5/12 of the cup

5 0

2 years ago

Please help, only two answers

Illusion [34]

Answer:

What I think are the answers are C,D, and A, hope this helps.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Sketch and shade the region in the xy-plane defined by the equation or inequalities.

Shtirlitz [24]

Answer:

attached below is the solution

Step-by-step explanation:

|x| < 7

= -7 < x < 7

| y | < 3

= -3< y < 3

attached below is the shaded region in the xy-plane

7 0

3 years ago

What is the value of m in the equation 1/2m-3/4n=16 when n=8

Jobisdone [24]

1/2m-3/4n=16
1/2m-3/4(8)=16
1/2m-6=16
1/2m=22
m=44
I hope this helped!

5 0

2 years ago

Read 2 more answers

At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more

I am Lyosha [343]

Answer:

The probability is $P( X \le 4 ) = 0.0054$

Step-by-step explanation:

From the question we are told that

The percentage that are on time is p = 0.76

The sample size is n = 11

Generally the percentage that are not on time is

$q = 1- p$

$q = 1- 0.76$

$q = 0.24$

The probability that no more than 4 of them were on time is mathematically represented as

$P( X \le 4 ) = P(1 ) + P(2) + P(3) + P(4)$

=> $P( X \le 4 ) = \left n } \atop {}} \right.C_1 p^{1} q^{n- 1} + \left n } \atop {}} \right.C_2p^{2} q^{n- 2} + \left n } \atop {}} \right.C_3 p^{3} q^{n- 3} + \left n } \atop {}} \right.C_4 p^{4} q^{n- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{11- 1} + \left 11 } \atop {}} \right.C_2p^{2} q^{11- 2} + \left 11 } \atop {}} \right.C_3 p^{3} q^{11- 3} + \left 11 } \atop {}} \right.C_4 p^{4} q^{11- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{10} + \left 11 } \atop {}} \right.C_2p^{2} q^{9} + \left 11 } \atop {}} \right.C_3 p^{3} q^{8} + \left 11 } \atop {}} \right.C_4 p^{4} q^{7}$

$= \frac{11! }{ 10! 1!} (0.76)^{1} (0.24)^{10} + \frac{11!}{9! 2!} (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!} (0.76)^{3} (0.24)^{8} + \frac{11!}{7!4!} (0.76)^{4} (0.24)^{7}$

$P( X \le 4 ) = 0.0054$

4 0

2 years ago