Answer:
36000pi
Step-by-step explanation:
V = 4/3*pi*r^3 so we need to know r
we know surface area, which is 4pi*r^2=3600pi. so we can solve for r
r=30
so v = 4/3*pi*30^3 = 36000pi
Answer:
b = c - a - D
Step-by-step explanation:
The the number of construction toys that must be bought so that the profit for Jacelyn's company and Richie's company is the same. is t= 204.3269230769231
<h3>what is equation?</h3>
Equations are mathematical statements containing two algebraic expressions on both sides of an 'equal to (=)' sign. It shows the relationship of equality between the expression written on the left side with the expression written on the right side. In every equation in math, we have, L.H.S = R.H.S (left hand side = right hand side). Equations can be solved to find the value of an unknown variable representing an unknown quantity. If there is no 'equal to' symbol in the statement, it means it is not an equation. It will be considered as an expression.
As, per the given situation the equation can be
2125 + 49.99 t = 39.95 t
10.4 t= 2125
t= 2125 / 10.4
t= 21250/104
t= 204.3269230769231
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Answer:
C. P69,256.82
Step-by-step explanation:
We know that,
The amount formula in compound interest is,
Where, P is the principal amount,
are the annual rate for the different periods,
are the number of year for different periods,
are the number of periods,
Given,
A = P 200,000,
, 
, 
,
, 
, 
Thus, by the above formula the final amount would be,
Option C is correct.
Answer:
School collected 273 coats in second month.
Step-by-step explanation:
Given
Total number of coats collected in 2 months = 542
Number of coats collected in first month = 269
We need to find the number of coat school collected in second month.
Solution:
Now we can say that;
Total number of coats collected in 2 months is sum of Number of coats collected in first month and Number of coats collected in Second month.
Also We can say that;
Number of coats collected in Second month is equal to Total number of coats collected in 2 months minus Number of coats collected in first month.
framing in equation form we get;
Number of coats collected in Second month = 
Hence School collected 273 coats in second month.
